The secondary current is determined by the load, not by the transformer. But the load current mustn't continuously exceed the rated current of the secondary winding. To determine the secondary rated current, you need to know the rated secondary voltage of the transformer, and divide 315 kV.A by this figure.
Incidentally, the correct symbol for 'kilovolt ampere' is 'kV.A', not 'kva'.
It depends on the rated voltage of its secondary.
The primary current of a transformer depends upon the secondary current which, in turn, depends upon the load supplied by the transformer. There is not enough information in the question to determine the rated primary and secondary currents of the transformer.
If a step-up transformer has 200 turns on the primary coil and 3000 turns on the secondary coil, with a primary coil voltage of 90 volts and current of 30 amps, then the turns ratio is 200:3000, so the secondary voltage is 1350 voltage and the available current is 2 amps. (This ignores losses through the transformer.)
3
The formula for amps is I = W/E. Amps = 40/240 = .17 primary amperage. For the secondary amperage I = W/E. Amps = 40/24 = 1.7 amps.
The number of amps a transformer can carry on its secondary side depends on its power rating (in watts or VA) and the voltage of the secondary winding. You can calculate the current (in amps) using the formula: Amps = Watts / Volts. For example, if you have a 1000 VA transformer with a 10V secondary, it can carry 100 amps (1000 VA / 10V = 100A). Always ensure the transformer is rated for the desired load to avoid overheating or damage.
On a 1kva you have 1000 watts capacity. To fine the current the formula is I = W/E. The secondary side of the transformer has the capacity of 1000/120 = 8.3 amps. In your question you do not put the amps across the secondary you draw amps from it. Using the transformer to its maximum, without overloading it, the primary will be 4.16 amps at 240 volts and the secondary will be 8.33 at 120 volts. <<>> voltage times amps equals wattage
This typically has to do with how many amps you can safely pull from the secondary of the transformer.
To calculate the amperage in the secondary side of a transformer, you can use the formula: Amps = kVA / (Volts x Sqrt(3)). For a 250 kVA transformer with a 220-volt secondary, the amperage will be approximately 660.4 Amps.
It depends on the rated voltage of its secondary.
Find the wire from the secondary of the transformer. If it's a step-down transformer the thicker wire is the secondary. Measure its diameter in inches and calculate its cross-section area in square inches. The current rating for transformer wire is 1000 amps per square inch, or 1.55 amps per square mm.
The primary current of a transformer depends upon the secondary current which, in turn, depends upon the load supplied by the transformer. There is not enough information in the question to determine the rated primary and secondary currents of the transformer.
It depends on how many amps it was designed for. A 12.5kV/600v 10kVA 3 phase transformer can handle ~.5 amps on the primary and ~10A on the secondary. A 600/120V 10kVA 3 phase transformer can handle ~10A on the primary and ~50 on the secondary.
If a step-up transformer has 200 turns on the primary coil and 3000 turns on the secondary coil, with a primary coil voltage of 90 volts and current of 30 amps, then the turns ratio is 200:3000, so the secondary voltage is 1350 voltage and the available current is 2 amps. (This ignores losses through the transformer.)
3
Find the wire from the secondary of the transformer. If it's a step-down transformer the thicker wire is the secondary. Measure its diameter in inches and calculate its cross-section area in square inches. The current rating for transformer wire is 1000 amps per square inch, or 1.55 amps per square mm.
Assuming the transformer is ideal, the current on the primary side can be calculated using the formula for power: P(primary) = P(secondary). Since power is the product of voltage and current, the current on the primary side would be 1.38 amps (277V x Iprimary = 120V x 6A).