A: Vce is the voltage that will follow a particular load line. It is linear by itself but not related to the base drive.
well, this is very simple to understand ,the DC load line of a circuit is nothing but the Kirchoff's voltage law on the out put circuit of the transistor-amplifier. As the KVL is linear equation involving voltage drops the equation of load line is a straight linelet us assume that the transistor is in CE configuration.VCC-VCE-ICRC=0vICRC=VCC-VCE of the form by=aX+c which is in the form of a straight line with positive intercepts on X(VCC) and Y(VCC / RC) axis and a negative slopewhere,x= VCE/RCy= ICm(slope)= -VCC/RC
well the difference mainly exists in the method of finding them , these are :-1. in finding DC load line :-open all AC sourcesopen all the capacitors2. for AC load line:-open all the Dc sourcesshort all the capacitors.
when the dc supply given, dc load line lies in the Ic and Vcc. when the AC supply given, AC load line lies in the Ic and Vcc.
A load line is used in graphic analysis of circuits, having both linear and non-linear parts, representing the constraint the other parts of the circuit put on the non-linear transistor. It represents the response of the linear circuit connected to the transistor. The DC load line describes the DC operation of a transistor graphically.
Voltage has nothing to do with it. THE LOAD LINE ON THE OTHER HAND HAS EVERYTHING TO DO WITH IT.
well, this is very simple to understand ,the DC load line of a circuit is nothing but the Kirchoff's voltage law on the out put circuit of the transistor-amplifier. As the KVL is linear equation involving voltage drops the equation of load line is a straight linelet us assume that the transistor is in CE configuration.VCC-VCE-ICRC=0vICRC=VCC-VCE of the form by=aX+c which is in the form of a straight line with positive intercepts on X(VCC) and Y(VCC / RC) axis and a negative slopewhere,x= VCE/RCy= ICm(slope)= -VCC/RC
well the difference mainly exists in the method of finding them , these are :-1. in finding DC load line :-open all AC sourcesopen all the capacitors2. for AC load line:-open all the Dc sourcesshort all the capacitors.
when the dc supply given, dc load line lies in the Ic and Vcc. when the AC supply given, AC load line lies in the Ic and Vcc.
A dc load line is formed by joining the 2 points wherin the slope is equal to the inverse of the load resistance.. whereas the ac load lin has a different slope... and it intersects the dc load line at the quiescent point.
cutoff and saturation
It depends on the total load of the transistor as to what the shape of the slope is for the DC load line. A transistor gains voltage as base current is allowed to flow.
A: A transistor has voltage gain as base current is allow to flow. If the load is constant then a DC mirror azimuth path can be plotted as a function of base current and collector current and that is the load line
A load line is used in graphic analysis of circuits, having both linear and non-linear parts, representing the constraint the other parts of the circuit put on the non-linear transistor. It represents the response of the linear circuit connected to the transistor. The DC load line describes the DC operation of a transistor graphically.
The cut-off point is the exact point where the load line crosses with the vector axis. The saturation point is the point where the load line intersects with the collector current axis.
Voltage has nothing to do with it. THE LOAD LINE ON THE OTHER HAND HAS EVERYTHING TO DO WITH IT.
The dc load resistance is Rc but the AC Load resistance is (RcRl). If a load line is drawn the slope of which is -1(Rc Rl) . Then it is called an AC load line and it is to be used when the transistor is operating as an amplifier.
operating point of dc load line refers to point where there is no signal either no amplification use to take place as base current is zero(in case of common emitter configuration) and it is represented by Q.......