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How will an electrical circuit behave if there is an open circuit?
The circuit is incomplete, you will have no continuity, no flow of current to the load or other components. The voltage across every component in the circuit is zero. No part of the circuit stores or dissipates any energy. In short, the circuit doesn't work.
What is the difference between voltage forward voltage and voltage drop?
Voltage is the potential difference between the source & any point in the circuit. The forward voltage is the voltage drop across the diode if the voltage at the anode is more positive than the voltage at the cathode (if you connect + to the anode). Voltage drop means, amount of voltage by which voltage across load resistor is less then the source voltage.
Why kirchhoff's voltage law is applicable for open circuit?
Kirchoff's Voltage Law does not work, per se, for open circuits. You need a closed circuit for it to make any kind of sense.The signed sum of the voltage drops going around a series circuit is equal to zero.That means you have a closed circuit.However, it can be argued, correctly, that an open circuit is simply one that has two nodes with infinite resistance between them. Assuming that all of the other nodes have something less than infinite resistance between them, then Kirchoff's law does work, of sorts, in that the voltage drop across all nodes that are not voltage sources will be zero, because there is no current, and the voltage drop across the two nodes with infinite resistance will be equal to the sum of the voltage rises across the voltage sources. Current sources in such a circuit will not work, because, with zero current, they would attempt to generate infinite voltage.AnswerKirchhoff's Voltage Law does indeed apply to an open circuit, because the voltage drop across the open part of the circuit is numerically equal to the supply voltage and, hence, the algebraic sum of the voltage drops around that particular loop is zero.Kirchoff's Voltage Law does not work, per se, for open circuits. You need a closed circuit for it to make any kind of sense.The signed sum of the voltage drops going around a series circuit is equal to zero.That means you have a closed circuit.However, it can be argued, correctly, that an open circuit is simply one that has two nodes with infinite resistance between them. Assuming that all of the other nodes have something less than infinite resistance between them, then Kirchoff's law does work, of sorts, in that the voltage drop across all nodes that are not voltage sources will be zero, because there is no current, and the voltage drop across the two nodes with infinite resistance will be equal to the sum of the voltage rises across the voltage sources. Current sources in such a circuit will not work, because, with zero current, they would attempt to generate infinite voltage.Read more: http://wiki.answers.com/Why_kirchhoff's_voltage_law_is_applicable_for_open_circuit#ixzz1i2fWNqfN
What is voltage drop in parallel circuit?
First calculate your resistance for your parallel circuit using the reciprocal formula1/1/r1+1/r2 etc... Get that total and then add it to your resistance total of your series circuits. Divideyour applied voltage EA by Resistance Total RTthis gives you your current total or IT. Calculate your voltage drops by multiplying IT by your resistors in the series circuit. Subtract those voltage drops from your applied voltage EA and you now have your voltage drops for your parallel circuit, which all are equal to each other.
What is the definition of applied voltage?
Any voltage that is fed into or "applied" to an electrical circuit is referred to as an "applied voltage".
What parts of a circuit acts as a resistor?
Any part of a circuit that has a voltage drop across it is a resistor.
How will an electrical circuit behave if there is an open circuit?
The circuit is incomplete, you will have no continuity, no flow of current to the load or other components. The voltage across every component in the circuit is zero. No part of the circuit stores or dissipates any energy. In short, the circuit doesn't work.
Can a switch in the off position cause an electrical short circuit?
No, once the switchis openedthere is no longer any voltage in the circuit to short out against.
What is short circuit voltage?
Short circuit voltage is the voltage that has to be applied to the primaries of a transformer, so that the nominal current flows through the secondaries, when they are shorted. This value is important, if transformer secondaries shall be used in parallel. Ideally all transformers with parallel secondaries should have the same short circuit voltage. When their short circuit voltages are different, the transformer with the lower short circuit voltage will be loaded more than their relationship of power ratings would predict. The short circuit voltage is also important in the design of a transformer, because it predicts, how much the secondary voltage will drop at nominal output current. This knowledge helps the designer to find out, how many further windings the secondary needs for a certain voltage in relation to an ideal transformer. Short circuit voltage is also known as impedance voltage.
In a parallel circuit what is the total current equal to?
In all branches of a parallel circuit, it is voltage that is the same. Across each parallel branch of a circuit, we'll measure the same voltage. Probably the best example of equal voltages appearing across all branches of a parallel circuit is a household electrical distribution curcuit. The voltage at any outlet where you'd care to plug in an appliance or device will be the same. A fan plugged into an outlet in a bedroom will "feel" the same voltage as it would if it were in the living room and plugged into an outlet there.One other way to look at things like this is that each branch of the parallel circuit is connected across the voltage source. Each branch could be looked at as an "independent" circuit, and any given branch doesn't care what is happening in any other branch. Does turning that fan we mentioned on and off, or even unplugging it from the outlet affect the operation of, say, the refrigerator? No, it does not. Any device plugged into an outlet is connected "directly" to the source of voltage. And each parallel branch of the circuit will operate independently of any other branch. We know that the voltage in (or across) any branch of a parallel circuit is the same as the voltage across any other branch.
What are the characteristic of series circuit?
In a series circuit the current remains constant at any point while the voltage drops across each resistive element.
Is current source available in any circuit?
The question is vague.A current source is the short form of constant current source.A voltage source, on the other hand, is the short form of constant voltage source.That being so, then no, a current source is not available in any circuit.
Can voltage across an element be greater than the applied voltage in an ac circuit?
Yes, if there is a step up coil in the circuit. Coils can change voltage and amps in any given circuit. If the voltage is increased, than the amperage is decreased (or vice versa). This is how an ignition coil in a car works. A 14 volt auto electrical system can have 1000 volts across the spark plugs. Without a coil, I know of no other way voltage in any part of a circuit can be higher than applied voltage. A 1000V? TRY 30 KV TO 40 KV @80-100MW
What is common to both thevenin and norton theorem?
To solve any D.C. circuit by using Thevenin Theorem,First of all load resistance RL is disconnected from the circuit and open circuit voltage across the circuit is calculated (known as Thevenin equivalent voltage)Secondly, the battery is removed by leaving behind its internal resistance. Now we calculate equivqlent resistance of the circuit ( called Thevenin equivalent resistance).Now we connect Thevenin Voltage in series with Equivalent resistance of the circuit and now connect load resistance across this circuit to calculate current flowing through the load resistance.Whereas in the case of using Norton theorem, we again remove the load resistance if any, and then short circuit these open terminals and calculate short circuit current Isc.Second step is same as in Thevenin theorem i.e. remove all sources of emf by replacing their internal resistances and calculate equivqalent resistance of the circuit.Lastly, join short circuit current source in parallel with equivalent resistance of the circuit. Now, we can calculate votage across the resistance which was connected in parallel with Isc.So, by knowing the open circuit voltage, we can calculate current flowing the resistance and on the other hand , by knowing the short curcuit current , we can calculate voltage across the resistance.
When do you get a short curcuit?
A short circuit occurs when electricity can pass with little resistance between two parts of a circuit where it is not intended to. Typically, it will happen when two uninsulated wires touch accidentally, or a conducting (metal) part contacts two uninsulated parts of the circuit. It could also happen if the circuit is in contact with a conducting fluid such as saltwater. A short circuit can even happen through air if voltage becomes very high, enough to create an electrical "arc", overcoming the resistance of the air. In the worst case, a short circuit connects the positive and negative terminals of a battery or voltage source almost directly, with almost no resistance, and very high current results, which is dangerous. In other cases, the short circuit might not create any danger, because the path of electricity encounters resistance in another part of the circuit. However, the voltage difference across the short will be zero, and the voltage difference across the intended path between the endpoints of the short will also be zero. All the current will flow through the short, and none through the intended path. As a result that part of the circuit probably will not work.
What is the difference between linear and nonlinear problems and how do you?
A linear circuit is an electric circuit in which, for a sinusoidal input voltage of frequency f, any output of the circuit (current through any component, voltage across any component, etc.) is also sinusoidal with frequency f. Note that the output need not be in phase with the input.
Why the voltage drop across inductance and voltage drop across capacitance is greater than source voltage in series resonance circuit?
The reason for the total voltage drops across the capacitance and inductance IN AN AC CIRCUIT has to do with the different phase angles of the voltages.First, current is the same value and same phase angle everywhere in a series circuit. But, voltage across a capacitor lags current by 90 degrees (capacitor current leads voltage). Next, voltage across a pure inductance leads current by 90 degrees (inductor current lags voltage).The rule that all voltages in a series circuit have to add to the supply voltage still applies, but in this case, the voltage drops are added VECTORALLY, not arithmetically. If you were to graph this addition, you would show any resistance voltage in phase with the current, the capacitor voltage at -90 degrees to the current and the inductor voltage at +90 degrees to the current, for a phase difference between them of 180 degrees, cancelling each other out.In a series resonant circuit, the impedances of the capacitor and inductor cancel each other. The only impedance to the flow of current is any resistance in the circuit. Since real-life inductors always have some resistance, at least there is always some resistance in a series resonant circuit.
