For a circuit to get cold, the voltage across the circuit must decrease, and the resistance within the circuit must increase. This decrease in voltage reduces the energy flowing through the circuit, while the increase in resistance limits the flow of current, resulting in less heat generation. By manipulating these two factors, the circuit can be cooled down effectively.
A load is anything that draws current from a source of potential difference. A 'heavy' load will draw a larger current than a 'light' load. A resistor can certainly be used as a load. A low resistance will draw a larger current than a higher resistance and, so, a low resistance represents a high load while a high resistance represents a low load.
A lamp has two resistances: a 'hot' resistance (its operating resistance) and its 'cold' resistance (its resistance when switched off), and the hot resistance is significantly higher than its cold resistance.You can calculate its 'hot' resistance from its rated power and its rated voltage (assuming that it is being supplied at its rated voltage), by manipulating the following equation, to make Rthe subject: P= V2/RYou will, though, have to measure its cold resistance.
Diagrams are not supported with WikiAnswers, sorry, so you will have to use your imagination...A simple series circuit can be built with a battery, a switch, and a light bulb. One end of the battery is connected to one end of the switch. The other end of the switch is connected to one end of the bulb. The other end of the bulb is connected to the other end of the battery.If the switch is open, no current flows, and the bulb does not illuminate. If the switch is closed, current flows, and the bulb illuminates. By Ohm's law, the current through the bulb is proportional to the battery voltage and inversely proportional to the resistance of the bulb. Note, of course, that we are talking about hot resistance of the bulb, because cold resistance is an entirely different thing, due to the temperature coefficient of the bulb. Also, by Kirchoff's current law, the current at every point in this simple series circuit is the same and, by Kirchoff's voltage law, the voltage across the battery is the same as the voltage across the bulb.
By Ohm's law, resistance is voltage divided by current, so the resistance of a light bulb can be measured by observing the voltage across it simultaneously with observing the current through it. Interestingly, the hot resistance is significantly different that the cold resistance, so measuring resistance with an ohmmeter will not give a meaningful resistance. This is because the resistance of a light bulb has a positive temperature coefficient. Take a typical 60 W 120V light bulb, for instance... Its cold resistance is about 16 Ohms. Calculate current and power at 120 V and you get 7.5 A and 900 W. The truth is that at 60 W, the bulb pulls 0.5 A and has a resistance of 240 Ohms.
Ohm's Law: Resistance = Voltage divided by current110 volts / 2 amperes = 55 ohmsNote: This represents 220 watts, which is a considerable amount of power for a resistor. In all likelihood, the resistance will change as a result of that amount of power (heat) so the end result, 55 ohms, is only valid as an absolute number, in that 55 ohms is the answer, but the cold value of the resistor is uncertain.
If you have a lamp, you can assume that the resistance of the lamp when it is under power will follow the ohms law. BUT, one thing you must remember is, when a lamp is under load, it is glowing HOT. When metal is HOT, the molculoes of the meals are in much more active state. When this happens, the resistance will increase. Conversely, when the lamp is NOT on ON state, the filaments are cold. Moleculoes in the filaments are not as active. Thus, the resistance is lower. There is almost 10 to 1 difference in resistance from hot to cold. Taking out a multimeter and measuring the resistance of the lamp will not help you determine the resistance of the lamp when it is actually under load (with voltage applied) Really, the only thing you can do is to measure the voltage, measure the current, then arrive at the resistance mathmatically.
If the current through a pure metallic conductor causes the temperature of that conductor to rise, then its resistance will increase. A practical example of this is an electric lamp. The cold resistance of a lamp is very much lower than the hot resistance.
A load is anything that draws current from a source of potential difference. A 'heavy' load will draw a larger current than a 'light' load. A resistor can certainly be used as a load. A low resistance will draw a larger current than a higher resistance and, so, a low resistance represents a high load while a high resistance represents a low load.
When a circuit gets cold, the electrical resistance of the components may increase. This increased resistance can lead to a decrease in current flow through the circuit as Ohm's Law states that current is inversely proportional to resistance. Additionally, some materials, like semiconductors, may exhibit changes in conductivity with temperature, affecting current flow as well.
A lamp has two resistances: a 'hot' resistance (its operating resistance) and its 'cold' resistance (its resistance when switched off), and the hot resistance is significantly higher than its cold resistance.You can calculate its 'hot' resistance from its rated power and its rated voltage (assuming that it is being supplied at its rated voltage), by manipulating the following equation, to make Rthe subject: P= V2/RYou will, though, have to measure its cold resistance.
V=I*R Where: V is voltage I is the current in ampers R is resistance in ohms. So, if the current is 15 A and the resistance is 5 ohms, then the voltage must be 15 A *5 ohms = 75 V.
The resistance of a light bulb is inversely proportional to its temperature, i.e. a cold bulb has less resistance than a hot bulb. As a result, if you connect three bulbs in series to the same voltage used for one, they will each receive one third of the original voltage, causing them to use less power, causing them to generate less heat, causing them to have less resistance. If you measure the current in the circuit, there will be slightly more than one third of the original current. Given the same voltage, that means that each bulb has less resistance than originally measured, as expected. This characteristic of light bulbs is why they tend to blow out at turn-on. The starting current and power is higher than in the steady state case. You can make a bulb last much longer if you provide a soft start circuit that ramps up the voltage over a short period of time.
Power is voltage squared, divided by resistance (P = V2/R) so, for a given voltage, the lower the resistance, the greater the power!
Diagrams are not supported with WikiAnswers, sorry, so you will have to use your imagination...A simple series circuit can be built with a battery, a switch, and a light bulb. One end of the battery is connected to one end of the switch. The other end of the switch is connected to one end of the bulb. The other end of the bulb is connected to the other end of the battery.If the switch is open, no current flows, and the bulb does not illuminate. If the switch is closed, current flows, and the bulb illuminates. By Ohm's law, the current through the bulb is proportional to the battery voltage and inversely proportional to the resistance of the bulb. Note, of course, that we are talking about hot resistance of the bulb, because cold resistance is an entirely different thing, due to the temperature coefficient of the bulb. Also, by Kirchoff's current law, the current at every point in this simple series circuit is the same and, by Kirchoff's voltage law, the voltage across the battery is the same as the voltage across the bulb.
By Ohm's law, resistance is voltage divided by current, so the resistance of a light bulb can be measured by observing the voltage across it simultaneously with observing the current through it. Interestingly, the hot resistance is significantly different that the cold resistance, so measuring resistance with an ohmmeter will not give a meaningful resistance. This is because the resistance of a light bulb has a positive temperature coefficient. Take a typical 60 W 120V light bulb, for instance... Its cold resistance is about 16 Ohms. Calculate current and power at 120 V and you get 7.5 A and 900 W. The truth is that at 60 W, the bulb pulls 0.5 A and has a resistance of 240 Ohms.
For me different types of materials respond differently to temperature changes. A computer engineer designing a circuit must be able to predict if the conductivity of each material in the device will be within an acceptable range over the expected temperature range of operation of the device.
The resistance value for linear resistance is changed by changing the wavelength of the current or by installing additional resistors in the circuit. This restricts the amount of electricity which flows through the wiring.The resistance value for the linear resistance can be changed through strain over time. It can also be changed by changes in temperatures, such as going from hot to cold.