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conclusion of dc power supply 9V
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How do you reduce power consumption of a Wheatstone Bridge without changing the bridge resistances?
It seems to me that there are two methods. Reduce the supply voltage to the bridge, or reduce the time that the supply voltage is connected (you could also apply both methods simultaneously). Which is best depends on the details of the application. 1. Reducing the supply voltage: The power consumption of the bridge will be proportional to the square of the supply voltage so halving the voltage will quarter the power consumption. It will also halve the voltage at the detector for any given imbalance so, to maintain the same resolution, the sensitivity of the detector needs to be increased by the same factor as the voltage. Clearly there are limits to this as the imbalance signal will eventually be lost in noise. 2. Reducing the time the supply is connected: It is possible to pulse the supply voltage and the power consumption will be reduced in proportion to the duty factor. Clearly the detector must be fast enough to take a reading during the time that the supply is connected. This might be done using a microcontroller - an output controlling the supply to the bridge and an A/D input to measure the imbalance signal.
What size generator 1200 amps?
First you need to specify what voltage you require the generator to supply...Lets Assume its 240 Volts AC. Watts=Volts x Amps so 240x1200= 28.8 Kw. Then you have to take the efficiency of the generator into account. Mechanical power in is usually quite a bit more than the electrical power you get out...The difference is mostly the mechanical and thermal losses added together. If we say the generator is 70% efficient then you will need a generator 30% more powerful to supply a constant 1200 Amps...Thats a generator of about 38-40 Kw.
How do you wire into a kill switch?
You have to get into the wiring between the stator and the coil to break the power side or to take the power side to gnd and stop the coil from charging. If your still guessing its best to take it to a small engines place and let them do it for $20.
What would happen if you tried to operate a dc permanent magnet motor from an ac supply?
Apart from a lot of loud humming, the motor would not turn, it would take a lot of current and, if the circuit breaker did not trip to cut the supply of current, it would probably overheat or might even catch on fire.
Is the heat loss and current of a resistor affected by being in a parallel circuit or can you just calculate it the same as in series?
The heat generated by any particular resistor depends (at least electrically) solely on the power it dissipates. Power dissipation in a resistor is equal to current squared times resistance, and the current through the resistor is equal to the voltage across it divided by the resistance. If we take a 10 ohm resistor ('your resistor') and put it in a series circuit such that there is 10 volts across your resistor, the current through it will be 1 ampere (10/10=1). the power dissipated will be 10 watts (1^2 * 10=10). If we put your resistor in a parallel circuit that also puts 10 volts across it, then the current and power will be the same. Your resistor does not know or care where the voltage came from. From this point of view, once you get down to the voltage across the resistor, it does not matter what type of circuit it is in. On the other hand, for any given power supply voltage, then the type of circuit and the value of external components certainly does affect the terminal voltage and thus the current through as well as the power dissipated by the resistor. In a parallel circuit, the voltage across your resistor remains basically the same no matter what resistance you put in parallel with it (unless you overload the power supply or the power supply has high internal resistance). In this case, the voltage across the resistor is the same as the power supply, current is I=E/R, R being that resistor only, and power is P=I^2 * R. In a series circuit the current through the resistors is I=E/R, R being the total resistance (including the other resistor(s)). The power dissipation in your resistor will then be P=I^2 * R, I being the series current we just calculated, and R being your resistor only. Since the other resistors affect the current, and since the current is the same no matter where you measure in a series circuit, then the voltage across your resistor and thus the power dissipation will be affected. The voltage across your resistor will be E=I*R, I being the series current we just calculated, and R being your resistor only. So, while the calculation for power dissipated in a particular resistor does not change relative to what type of circuit it is in, the calculation to arrive at the voltage across the resistor and/or the current through it (which you will then need to calculate power) does. Keep in mind there are other mechanical parameters that influence the actual case temperature of the resistor. Physical size of the case, composition, and airflow velocity, if any, will alter the case-to-ambient thermal conductivity. Ambient temperature will also be a factor in the final temperature.
The fan in a 250-watt power supply is malfunctioning. what action should you take?
Remove and replace the power supply.
What is the first step you should take when testing a power supply?
You first have to know the type of power supply your are testing. Then you could test whether the power supply is receiving anything from its source. Next check if it is giving any output.
What is the power supply for?
The computer's power supply powers the computer or any other device. If you want more about power supplies take a look at the link provided below.http://en.wikipedia.org/wiki/Power_supply
How to check the power supply section of motherboard not the smps?
You should not bother to check any power supply in the motherboard. You need to take the motherboard to service centre if faulty.
What approach can you take if your computer simply does not power on and there is no lights on?
Check the power supply, if its good then your bios might be at fault.
How are series circuits and parellel circuits alike?
Both take current and energy from the power supply and dissipate power.
How is a series circuit and a parallel circuit alike?
Both take current and energy from the power supply and dissipate power.
Can the power supply cause the computer to be difficult to turn on?
Yes. If the power supply is of a low wattage and has too many pieces of hardware connected to it, it can. Try buying a power supply with a wattage over 300. One thing to check before replacing the power supply is the voltage selector in the back. If you use 120 volt power, then setting the power supply to 240 volts will cause the PC to only get half of the power it needs. External peripherals with their own power supply will not impact the power supply or current in the computer. Printers and monitors usually get their power from the wall socket, not the computer, and the same goes for external modems that plug into the wall. Keyboards and mice take negligible power.
What is the problem of your lg21sa3rl-l4 tv no power supply?
i had the same problem just take it to an expert
Do all apple macs take 100V-240V power supply?
only the iMac and the mac Pro
What is Redundant Power Supply?
A redundant power supply is two or more units in one package, where each can supply the full amount of power to the system, such that if one fails, the other will take over and the system never goes down. In most modern redundant power supplies, the dead one can be replaced while the system is still running, called hot-swapping.
Why do the Taliban take things from afghans?
In order to strike fear into the public and implicate power. They also do it to supply themselves.
