Ohm's Law states that Voltage = Resistance (Ohms) * Current (Ampere).
So when you increase voltage, you increase current.
Adding a seound battery to a series circuit will increase the voltage, and require less current to keep the lights (if there are any on) as bright. Say you have a 6v battery, then you add another 6v battery. the voltage of the circuit would be 12v
Voltage sources connected in parallel should have equal voltage. Otherwise the stronger battery would attempt to charge the weaker creating a lot of heat and depending on the type of battery there is the chance of explosion.
You can't make a DC voltage multiplier at all. You'd have to use the battery to power some sort of active power supply which, internally, would either oscillate or switch to create changing voltage, then step the voltage up through a transformer, then rectify and filter the higher-voltage AC, and hand you the higher DC at its output. You would use a significant and probably unacceptable percentage of the battery energy just to run the power supply. In other words, the battery would run the motor for an unreasonably short time before you would need to replace or recharge the battery. Look at the power requirement alone! If the 180V motor needs only 1 Amp to run, then the motor is gorging on 180 watts of power. To deliver only that much power at 12 volts, you would need to draw 15 Amperes from the battery, and that doesn't even yet account for power lost in the intermediate power supply.
If the ratio of voltage to current is constant, then the circuit is obeying Ohm's Law. If the ratio changes for variations in voltage, then the circuit does not obey Ohm's Law.
Ohm's law: voltage is current times resistance. Restating this; current is voltage divided by resistance, so increasing resistance would decrease current.
You could replace it with a battery with a higher mAh rating and the battery would last longer between charges. Increasing the voltage (V) may lead to better performance, but it could severely damage the electronics. I would highly recommend NOT increasing the voltage. You could get more than twice the lifetime with an NiMh battery instead of an NiCd. You will need an NiMh compatible charger. I would highly recommend NiMh over NiCd.
Test the voltage of the battery. if the voltage is below the rating of a new battery (For a CR203 it would be 3.6 volts) it is defective.
This would only happen if resistance was increasing faster than the rise in voltage.
Yes it would start glowing more brightly but at a certain point it would burn ou if you go on increasing the power.
The battery would likely not fit in the holder. Although it would provide the correct voltage, it would not last as long as the proper battery would.
Putting a piece of iron or steel inside the coil makes the magnet strong enough to attract objects. The strength of an electromagnet can be increased by increasing the number of loops of wire around the iron core and by increasing the current or voltage.
Defective voltage regulator.
The voltage would 9V minus any drop in the battery.
The battery gauge in a vehicle will move when you use your power mirrors as your causing a small drain on the battery & lowering the voltage slightly. The effect is normally only really visible when the engine is not running.
There are a few ways one can measure battery voltage. One would be to take it to an auto store like Auto Zone or Advance Auto Parts where they usually have battery voltage meters. If one would like to do it on their own, they would need to purchase a volt meter to test the battery life and to see if any cells are dead.
voltage would go up typically (you would raise the voltage, not the fan circuit), but it depends on the motor
If the voltage regulator (usually located inside the alternator) were to go bad and not limit voltage to the battery quite possilby _yes