A: Adding any resistance bulbs or whatever in a series circuit will reduce current and will reduce total power. In this case the bulb will glow dimmer as any additional bulbs are placed in the series circuit. this is true if the same input source is kept constant.
You increase the ohms ( resistance ). Because the bulbs are wired in series the ohms are doubled to start with so you are increasing it slightly more than the ohms of the individual bulb. Also, if one of the bulbs blows the bulbs will all go out because the circuit will be open.
In a series circuit, if another bulb is added, it is going to dim.
The circuit has to supply extra power and current, which is OK provided the maximum current limit is not exceeded.
they are not as bright
No. The resistance in a series circuit is all the resistor values added together. eg. If two resistors were in a circuit, one was 10 ohms and the other was 30 ohms, the resistance in the circuit would be 30 ohms. Hope this helps!
Depends on the device. If it is a resistor and you have a fixed voltage then the circuit will obey Ohms law. Voltage = Current x Resistance. So if R increases by adding more resistors in series and the voltage is constant, the current will decrease.
Assuming all of the individual batteries are the same voltage, if arranged in a parallel circuit the voltage is the same as any one battery. If arranged in a series circuit the voltage will be the sum (the total) of all of the batteries added together.
In a series circuit the total voltage is the sum of the voltage drops across all the component in series. When the voltage drops across each the individual components are added up, they will equal the supply (or applied) voltage.
an ideal ammeter has zero or negligible resistance when this is connected in series no effective resistance would be added in the circuit so that the value of curret that we get is exactly of the circuit only. but when the ammeter is connected in parllel as it has zero resistance , the resistor to which it is connected in parllel gets shorted and due to his the effective resistance of the circuit is changed and so the effective current ... due to this the w=value measured by the ammeter would be different (incresed due to dec. in effective resistance)
In a series circuit, if another bulb is added, it is going to dim.
Nothing would "happen" to them, but they would glow less brightly.
You raise the total resistance by that amount if added in series to a circuit. If you add them in parallel to a circuit then that total resistance will be less than the total of the added circuit.
A: For one thing the total capacitance will decrease . If the voltage rating are different then more problem will become evident. That is if they are added in series.
No it's series circuit.
series
In the circuit where the DC motor is added, it was not specified whether the motor was added in series or in parallel to circuit elements. If it was added in series, it will increase circuit resistance and it will cause circuit current to go down. In parallel, the motor will reduce total circuit resistance, and circuit current will increase.
The total current in the circuit will decrease.
Ammeters are added in series to the circuit to be monitored.
If you added more batteries in parallel, then the bulb would shine for a long time. If you added more batteries in series, then the bulb would burn very brightly for a short time and then 'burn out'.
No. The resistance in a series circuit is all the resistor values added together. eg. If two resistors were in a circuit, one was 10 ohms and the other was 30 ohms, the resistance in the circuit would be 30 ohms. Hope this helps!
Ohm's Law answers your question. Voltage = Current x Resistance. In a series circuit you are in effect adding resistance. If the Voltage remains constant then the answer is obvious looking at the equation above.