As we know that P=VI, and P is a constant value for any particular motor, so if the voltages will drop current will increase so that the product of V and I be the that particular constant value for any particular motor
The line current would be the same if the motor were connected in delta. The current can be based on the rule of thumb which says 7 amps must be allowed for a 1-HP single-phase motor on 240 v. A 2.2 kW motor is three times as powerful, and on a three-phase supply of the same voltage (240/415) it would draw 7 amps.
a voltage source has very less(negligible)resistance.thus is considered as a short.if connected in parallel to a resistor will draw all the current acting as a short.thus is always connected in series of a resistor.where as a current source has tremendous resistance(infinity).thus if connected in series will be conidered as an open branch and no current will flow through it other than the source current.
Yes. they should. The windings in a three phase motor are identical, and provided they are fed with a supply that has the phases at the correct voltage, and at the correct 'phase angles' to each-other, they should each draw the same current from each supply line. (Motor windings are a 'balanced' load - they will all draw the same current from the lines if the supply is okay and the windings are connected correctly, and have no shorts or opens in them.) Some three phase motors can be connected to run off of a single phase line, using capacitors to give phase shifts to simulate 3 phase. This is an 'unbalanced' 3 phase supply as far as the motor is concerned, and while it WILL work, the motor will develop less staring torque, less full load power, and more noise - and it WILL draw different currents in each 'phase' while running.
Maximum current is defined by the rated KW of the device, say Motor. The motor may not run at its maximum rated capacity all the time. Nominal current is drawn when motor runs at nominal load.
Depends on the voltage. If you are running off 120 VAC, a 0.5 horsepower motor would draw 3.1 A.
To answer this question a voltage must be stated.
The line current would be the same if the motor were connected in delta. The current can be based on the rule of thumb which says 7 amps must be allowed for a 1-HP single-phase motor on 240 v. A 2.2 kW motor is three times as powerful, and on a three-phase supply of the same voltage (240/415) it would draw 7 amps.
a voltage source has very less(negligible)resistance.thus is considered as a short.if connected in parallel to a resistor will draw all the current acting as a short.thus is always connected in series of a resistor.where as a current source has tremendous resistance(infinity).thus if connected in series will be conidered as an open branch and no current will flow through it other than the source current.
It depends on the construction of the motor. If the field winding is connected in series with the armaturewinding, the motor is like a universal motor and will probably operate normally. If the field winding is connected in parallel with the armature, the motor will not run, but will draw current, make noise and get hot.
To calculate the current drawn by the 100W electric fan motor when plugged into a 240V socket, you can use the formula: Current (A) = Power (W) / Voltage (V). Therefore, Current = 100W / 240V = 0.42 Amperes. So, the motor will draw approximately 0.42A of current.
What effect will be there on the motor (Induction) output power when a 100kW 50hz motor is connected to a 60hz power supply.
-- A stack of several cells connected in series presents several times the voltage of a single cell. -- The current depends on the 'load' connected between the battery's terminals. But since the current through any load is directly proportional to the voltage across it, several cells in series ... with their increased voltage ... will produce several times as much current as the same load would draw from a single cell.
Depending on the type of DC motor, it will either run normally or just heat up and make noise.i think the motor will rotate to and frow.means it will rotate in clycle.it will complete half cycle.and after it will complete its other half cycle in anticlockwise direction.
To answer this question the voltage of the motor must be stated.
For a 1hp 3-phase motor, the current draw will depend on the voltage supply. Typically, at 230V, a 1hp 3-phase motor will draw around 3.6 amps. However, this value may vary based on the motor efficiency and power factor.
In phantom loading,less power is consumed as the current and voltage coils are connected seperately;but in direct loading a load is connected which draw a considerable power.
1 horsepower is equal to 0.7456 kWatts, therefore 1.1184 kWatts will be the power consumption of that motor. The current draw depends on the voltage, simply use the P=UxI or I=P/U formulas to figure out the current draw (P=1118.4 Watts). some voltages: 12Vdc draw 93.2Amps 24Vdc draws 46.6Amps 110Vdc draws 10.17Amps 230Vdc draws 4.86Amps