Current
V = IR Where, V = voltage I = current R = resistance Thus if resistance is increased with constant voltage current will decrease
If the ratio of voltage to current is constant, then the circuit is obeying Ohm's Law. If the ratio changes for variations in voltage, then the circuit does not obey Ohm's Law.
Yes, if the resistance remains constant. Power is voltage times current, and current is voltage divided by resistance, so power is voltage squared divided by resistance. In essence, the power increases as the square of the voltage.
In a d.c. circuit, voltage drop is the product of resistance and current through that resistance.
The resistance of the circuit will be 46 ohms
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
If the resistance increases, while the voltage stays the same, current will decrease. Current = voltage divided by resistance
It is halved. coz voltage=current * resistance
V = IR Where, V = voltage I = current R = resistance Thus if resistance is increased with constant voltage current will decrease
No it cant. Voltage = Current x Resistance. So at constant Voltage if the Resistance is increased, Current will reduce
ohms law calculation for a series circuit - Total Resistance = Total Voltage divided by Total Current
If you double the voltage in a circuit, the power is quadrupled, assuming the resistance stays the same.
To increase (current) flow in a circuit you increase voltage (or decrease resistance). Ohm's Law: Current = Voltage divided by resistance
When you add resistance to a circuit, current goes down. Ohm's Law: current = voltage divided by resistance.
Since current = voltage / resistance, I = V/R, the current in a circuit will double if either the voltage doubles, or the resistance is halved.