120 volts into 30 ohms will produce 4 amps.
Ohm's Law: Current equals Voltage divided by Resistance.
Caution: Don't try this. The power in this case would be 480 watts, and an ordinary resistor would be destroyed by the heat generated, and might explode and catch fire.
V=IR, V=120 VOLTS R=30 OHMS I=V/R, I=120/30, I = 4Amps
4 resistors were connected in parallel it yields 5A of current from 220V supply.
The 12V battery connected to the 2.4 Ohm combination will supply 12/2.4 or 5A. The individual currents will be 12/3 or 4A for the 3 Ohm resistor, and 12/12 or 1A for the 12 Ohm resistor. The 2.4 Ohm parallel combination is obtained from a simple product-over-the-sum calculation.
When a dc supply is connected to a resistor, current flows. The current in amps is equal to the supply voltage divided by the resistance in ohms. The power used is the voltage times the current, and that appears as heat in the resistor, which might become hot to touch.
The electric heater is basically a resistor, designed to have the right resistance to draw the required current. So a 2 kW heater designed for a 230 v supply is really a resistor of 28.8 ohms, so when it's connected the current is 8 amps and the power is 2 kW.
A 120V power supply connected to a 30 Ohm resistor will produce 120/30 or 4 amps of current.
The current flowing through the resistor can be calculated using Ohm's Law, which states: Current (I) = Voltage (V) / Resistance (R). Plugging in the values given, the current would be 12 amps.
If a 9V supply is connected to a 100-ohm resistor, then the current is not 2 Amps,or even close to it.I = E/R = 9/100 = 0.09 amp.
V=IR, V=120 VOLTS R=30 OHMS I=V/R, I=120/30, I = 4Amps
When a resistor and an inductor are both connected to an AC supply, the current in the resistor is in phase with the voltage, while the current in the inductor is a quarter-cycle (90 degrees) behind. Supposing they both draw 1 amp on a 12-volt AC supply. The resistor will dissipate 12 watts, while the inductor will dissipate no power. Any power that enters the inductor comes back to the generator in a later part of the cycle. But the current drawn from the supply is 1.414 amps, so this would be a load with a power factor of 0.707.
4 resistors were connected in parallel it yields 5A of current from 220V supply.
The 12V battery connected to the 2.4 Ohm combination will supply 12/2.4 or 5A. The individual currents will be 12/3 or 4A for the 3 Ohm resistor, and 12/12 or 1A for the 12 Ohm resistor. The 2.4 Ohm parallel combination is obtained from a simple product-over-the-sum calculation.
The equation for such circuits is given by: V=R*I +(1/C)*Integration(idt)
The supply voltage in a parallel circuit remains the same regardless of the number of additional resistors connected. The voltage across each resistor in a parallel circuit is the same as the supply voltage. Adding more resistors in parallel will increase the total current drawn from the supply.
When a dc supply is connected to a resistor, current flows. The current in amps is equal to the supply voltage divided by the resistance in ohms. The power used is the voltage times the current, and that appears as heat in the resistor, which might become hot to touch.
The electric heater is basically a resistor, designed to have the right resistance to draw the required current. So a 2 kW heater designed for a 230 v supply is really a resistor of 28.8 ohms, so when it's connected the current is 8 amps and the power is 2 kW.
You can measure the current and power of a 'power supply', using an ammeter and a wattmeter. With the power supply connected to its load, the ammeter must be connected in series with the power supply's input. The wattmeter's current coil must also be connected in series with the power supply's input, and its voltage coil must be connected in parallel with the supply, taking the instrument's polarity markings into account.