C program for tribonacci series

Answer 1

#include<iostream>

int main()

{

int x=0, y=1;

std::cout<<x<<" ";

std::cout<<y<<" ";

while( y<1000000 )

{

std::cout<<(y+=x)<<" ";

x=y-x;

}

std::cout<<std::endl;

return(0);

}

Answer 2

#include

#include

main()

{

int n,i,c,a=0,b=1;

printf("Enter Fibonacci series of nth term : ");

scanf("%d",&n);

printf("%d %d ",a,b);

for(i=0;i<=(n-3);i++)

{

c=a+b;

a=b;

b=c;

printf("%d ",c);

}

getch();

}

Answer 3

#include<stdio.h>

#include<conio.h>

void main ()

{

int x,y,z,i;

clrscr();

printf("Enter 1st Term: ");

scanf("%d",&x);

printf("Enter 2nd Term: ");

scanf("%d",&y);

printf("Series is: \n");

printf("%d ",x);

printf("%d ",y);

for(i=1;i<=23;i++)

{

z=x+y;

printf("%d ",z);

x=y;

y=z;

}

getch();

}

Answer 4

#include<stdio.h>

#include<conio.h>

void main()

{

int a =1,b=0,c=0;

for(i=1;i<=n;i++)

{

printf("%d",c);

c=a+b;

a=b;

b=c;

getch();

}

Answer 5

I'm nearly 100% sure I'm doing your homework for you. If I am, then I really am disappointed. First of all, the name is "Fibonacci" and is detailed on wikipedia.

I'll just type it here and if it compiles, great, if not... I'm not going to do the whole assignment for you.

#include <stdio.h>

int main(int argc, char **argv)

{

int previousValueA = 0;

int previousValueB = 1;

int steps = 100;

int i;

int current;

printf("%d\n", previousValueA);

printf("%d\n", previousValueB);

for(i=0; i<steps; i++)

{

current = previousValueA + previousValueB;

previousValueA = previousValueB;

previousValueB = current;

printf("%d\n", current);

}

return 0;

}

Answer 6

#include void tribon(int n) { int a,b,c,d,i; b=1; c=0; d=0; i=1; while(i

Answer 7

#include <stdio.h>

unsigned long fib (unsigned long n) {

if (n 95, for 64 bit unsigned longs, due to integer overflow.