C programming to convert upper case string into lower case string and vice versa without using builtin function?

Answer 1

#include<stdio.h>

#include<conio.h>

void main()

{

char ch;

clrscr();

printf("Enter a Character");

scanf("%c",&ch);

if(ch>=65 && ch<=90)

ch=ch+32;

printf("Upper Case =%c",ch);

getch();

}

Answer 2

You can write a function that does it.

For example:

for( i = 0; i < strlen(string); i++){

if(string[i] >= 'A' && string[i] <= 'Z'){

offset = string[i] - 'A';

string[i] = 'a' + offset;

}

}

Answer 3

#include <ctype.h>

void main()

{

char s[30],st[30];

cout<<"enter the string in uppercase\n";

cin.getline(s,30);

int i;

for(i=0;s[i]!='\0';i++)

{

st[i]=tolower(s[i]); // see discussion

}

//st[i]='\0'; // see discussion

cout<<st;

getch();

}

Answer 4

Look into the toupper() and tolower() functions. To determine what case it is in, you could use its ASCII value: uppercase is 65 (A) - 90 (Z) and lowercase is 97 - 122.

You can use macros 'isupper' and 'islower' (they are in 'ctype.h' too).

Answer 5

#include<stdio.h>

#include<conio.h>

void main()

{

char ch,lower;

printf("Enter a Character\n");

scanf("%c%c",&ch);

if(ch>=65 && ch<=90)

{

ch=ch+32;

printf("\nupper Case =%c",ch);

}

else if(ch>=97 && ch<=122)

{

ch=ch-32;

printf("\nlower Case =%c",ch);

}

getch();

}

Answer 6

#include<stdio.h> #include<conio.h> char foo(char a) { if(a>=97 && a<=122) { a = a - 32; return (a); } else { return (a); } } void main() { char a[20],b[20]; int i=0; clrscr(); printf("Please enter a string: "); gets(a); printf("The String in Lower Case is: "); do{ b[i]=foo(a[i]); i++; }while (a[i]!=0); while(i<=20) { b[i]=0; i++; } printf("%s",b); getch(); }

Answer 7

as i can do it by adding 32 to the ascii value to each character of given string..

for example:-

void f(char *s)

{

while(s[i]!='\0')

{

s[i]=s[i]+32;

}

}

Answer 8

Ggdd