Yes.
The conditional operator is also known as ternary operator. It is called ternary operator because it takes three arguments. The conditional operator evaluates an expression returning a value if that expression is true and different one if the expression is evaluated as false.Syntax:condition ? result1 : result2If the condition is true, result1 is returned else result2 is returned.
An operand is the value that is being operated upon by an operator. For instance, the C++ increment operator (++) is a unary operator, which means it has only one operand, the variable that we wish to increment. This in the expression x++, x is the operand. The addition operator (+) is a binary operator and therefore has two operands. Thus in the expression x + y, x and y are the operands.
The NOT operator. E.g., NOT TRUE evaluates to FALSE while NOT FALSE evaluates to TRUE.
A ternary operator is an operator that requires three operands, as opposed to a binary operator that requires two operands and a unary operator that requires just one operand. C++ has just one ternary operator, the conditional ternary operator: <boolean expression> ? <expression #1> : <expression #2>; If the boolean expression evaluates true, the first expression is evaluated, otherwise the second expression is evaluated. A typical usage of this operator is to return the larger (or smaller) of two values of type T: template<typename T> T max (T a, T b) {return a<b ? b : a}; template<typename T> T min (T a, T b) {return a<b ? a : b}; These are really nothing more than notational shorthand for the following: template<typename T> T max (T a, T b) {if (a<b) return b; else return a; }; template<typename T> T min (T a, T b) {if (a<b) return a; else return b;}; However, because ternary expressions are evaluated, the return value of the expression can be used in more complex expressions: int a=42, b=0; // ... int c = ((a>b ? a : b) = 1); In the above expression, whichever is the larger of a and b will be assigned the value 1 which will also be assigned to c. Thus a and c become 1 while b remains 0.
A compile time operator is an operator involved in an expression where the result is known at compile time. An example is the expression 1 + 2 * 4. Since 1, 2, and 4 are literal expressions, the result is known at compile time, and there is no need to generate code to evaluate it. The compiler is free to substitute the expression 9 in place of the expression 1 + 2 * 4. Don't bother doing it yourself - sometimes the clarity of writing what you are trying to accomplish makes for more well documented code.If you do not have such a compiler, it is high time that you upgrade.
Fractions yfg
You have to include the expression in the question.
No, but you can rewrite it as an expression with exponents if you want.
you use your noggin
No, a unary expression consists of one operand and one operator
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radical expressiona radical expression
Variable expression.
It is an expression.
To simplify the expression log(log(n)), you can rewrite it as log(n) / log(10).