A compile time operator is an operator involved in an expression where the result is known at compile time. An example is the expression 1 + 2 * 4. Since 1, 2, and 4 are literal expressions, the result is known at compile time, and there is no need to generate code to evaluate it. The compiler is free to substitute the expression 9 in place of the expression 1 + 2 * 4. Don't bother doing it yourself - sometimes the clarity of writing what you are trying to accomplish makes for more well documented code.
If you do not have such a compiler, it is high time that you upgrade.
There is no such increment operator in C language to increment the value of a variable by 2.An increment operator only increments the value by 1. however you can apply the increment operator twice to get an increment of 3. No: you cannot: ++(++a) won't compile. Yes. Example: a += 2; but += is not an increment operator, it's a shorthand of a=a+2; just like a++ is a shorthand for a= a+1
It's a syntax error, which is detected during compilation, yes.
First, install a C-compiler.
calloc operator,malloc operator
addition operator subtraction operator product
The Sizeof () operator only works at compile time and doesn't evaluate anything at run time.
The sizeof operator is used to determine the length of its operand (in bytes). The operand must be a type or an object of a type (a variable). The operator is a constant expression and therefore executes at compile time. As such there is no runtime overhead in repeated use of the sizeof operator.
You can write, compile and execute C-programs in both DOS and Unix, if that's what you meant.
Sometimes, it is. Some implementations compile C++ code into C code, and then compile the C code.
Static memory allocation occurs at compile time where as dynamic memory allocation occurs at run time.
Not possible.
I had to compile a list of all the people who had seen the accident. Take these reports and compile a history starting with the oldest dates first. The doctor asked me to compile my medical history.
There is no such increment operator in C language to increment the value of a variable by 2.An increment operator only increments the value by 1. however you can apply the increment operator twice to get an increment of 3. No: you cannot: ++(++a) won't compile. Yes. Example: a += 2; but += is not an increment operator, it's a shorthand of a=a+2; just like a++ is a shorthand for a= a+1
+ += - -= * *= / /= % %= = == != <= >= & && | ^ ~ << <<= >> >>= , [] () are the basic operator in TURBO C
conditional operator , size of operator , membership operator and scope resulation operator can not be overload in c++
With GCC.
Yes we can compile a c program using c++ compiler. Because c++ evolved from the c. c++ have some additional features beyond c. c++ support almost all concepts used in c.