To determine the cubic feet per minute (CFM) of a 2-inch pipe at 90 psi, you typically need to consider factors such as the flow velocity, pressure drop, and whether the flow is laminar or turbulent. Using standard flow equations or charts for compressed air or fluid dynamics, a 2-inch pipe at 90 psi can generally deliver around 130 to 200 CFM, depending on the specific application and conditions. For precise calculations, it's advisable to consult flow tables or perform calculations based on the specific system design and requirements.
well, 100 gallons at 3000 psi is 3333 gallons at 90 psi, which is 443 cubic feet, or 110 minutes. However, most air tools are rated for cfm's at atmospheric pressure, which is 14.7 psi at the surface, so 2714 minutes. This is average usage, not continuous, but still quite a long time. Now, if you go down 33 feet, the pressure doubles, so you have to cut the time down - the actually calculation is hazy, as the ambient pressure doubles, but the pressure differential does not - however, you will need to increase the pressure going to the tool by 15 psi for every 30 feet of depth, or else it won't work right.
This depends on what your target pressure is. If the height of the pipe is H in feet, the pressure at the bottom of the pipe from the column of water is 0.036127292 * H * 12 where 0.036127292 is the density of water in lbs/in^3. Thus, if your initial water pressure is I, the pressure at H feet will be I - 0.036127292 * H * 12 So you will have Height | Pressure +--------- 0 ft | 40 psi 10 ft | 35 psi 20 ft | 31 psi 30 ft | 27 psi 40 ft | 23 psi 50 ft | 18 psi 60 ft | 14 psi 70 ft | 10 psi 80 ft | 5 psi 90 ft | 1 psi 100 ft | 0 psi One will be required above 90 ft. You'll probably want one above 40 ft. Derivations: eq means equals. This wiki eats equals signs. D eq diameter of the pipe in inches, H eqheight in feet D / 2 eq R Area (A)(in^2) eq pi * R ^ 2 Volume (V)(in^3) eq A * H * 12 eq pi * R ^ 2 * H * 12 Water weight (W)(lbs) eq V * 0.036127292 eq pi * R ^ 2 * H * 12 * 0.036127292 Pressure (P)(psi) eq W / A eq V * 0.036127292 eq pi * R ^ 2 * H * 12 * 0.036127292 / pi * R ^ 2 eq H * 12 * 0.036127292
The horsepower (HP) required to produce 12 bar (approximately 174 psi) of pressure depends on several factors, including the type of compressor, its efficiency, and the desired flow rate. A general rule of thumb is that a compressor needs about 1 HP for every 3.5 to 5 CFM (cubic feet per minute) of air at 90 psi. To determine the exact HP needed, you'd need to calculate the specific flow requirements and compressor efficiency for your application. Typically, you might expect around 5-10 HP for achieving 12 bar, but this can vary significantly based on the specific setup.
This depends on several factors. A smaller tank will have less air available at the same pressure than a larger tank. Also, the cubic feet per minute rating of the compressor is a factor, with a larger compressor rating allowing for more usage.
cut a 22 1/2 out of it
More cfm's more airflow. Yes, more is better when you are powering certain airtools. Check the air tool specifically to see the demands
There are 90 pounds per square inch (psi) in 90 pounds.
No, they are not equal. The volume of air at different pressures does not directly correlate in a linear manner. Pressure and volume are inversely proportional according to Boyle's Law, so as pressure decreases, volume increases and vice versa.
pipe size(inch)x38.1
What it's the take out off 12 inch 90
The take-off for a standard radius 90 is one and one half the diameter of the pipe. Example: 6 inch 90 has a take- off of 9 inches. The take-off for short radius 90 would be the dia. of the pipe. Long radius 90 is 2 times the pipe diameter.
14.7 gallons of water.
90 million Pascal is about 13,053 psi
well, 100 gallons at 3000 psi is 3333 gallons at 90 psi, which is 443 cubic feet, or 110 minutes. However, most air tools are rated for cfm's at atmospheric pressure, which is 14.7 psi at the surface, so 2714 minutes. This is average usage, not continuous, but still quite a long time. Now, if you go down 33 feet, the pressure doubles, so you have to cut the time down - the actually calculation is hazy, as the ambient pressure doubles, but the pressure differential does not - however, you will need to increase the pressure going to the tool by 15 psi for every 30 feet of depth, or else it won't work right.
you need a box before your pipe run has 360 degrees of bend, or 4, 90's
It would generally require around 4,000 pounds per square inch (psi) of force to crush an empty pop can. This force is needed to overcome the structural integrity of the can and compress it.
CFM (cubic feet per minute) is not directly related to horsepower unless a pressure is given with the CFM number. A 1 HP pump might only generate 2.5 CFM at 100 PSI, for example. That same 1 HP can push hundreds of CFM at standard air pressure (a large fan, for example).