Yes, bulbs in a circuit use up current by converting electrical energy into light and heat. When current flows through the filament of a bulb, it encounters resistance, which causes the filament to heat up and emit light. This process results in a decrease in the overall current available in the circuit, as some energy is consumed by the bulbs. However, the total amount of charge remains constant; it’s the energy that is transformed, not the quantity of current itself.
3 amps each
Assuming the bulbs are identical, the voltage drop across each one is inversely proportional to the number of bulbs. So, for example, 240V could power 20 12V bulbs in series. In addition, the circuit would have to be able to supply the necessary current.
In a parallel circuit, each component receives the same voltage, but if the bulbs are not compatible with the battery's voltage or if they are faulty, they may not light up. Additionally, if there is a short circuit or if the connections are improper, it can prevent the flow of current, resulting in no lights lighting up. Lastly, if the battery is depleted or has insufficient current capacity, it may not provide enough power for the bulbs to function.
Answer: it will burn out **Explain:**The same current flows through each part of a series circuit. If the circuit is broken at any point there won't be any current that will flow. In this case, if one of the bulbs blew out, the other bulb would not be able to light up because the flow of electric current would have been interrupted. #Carryonlearning
The bulb will shine as long as it is still part of a complete circuit. You probably have a diagram for such a circuit. See if you can still trace a path through the battery and one of the bulbs without passing through the other bulb. For comparison, try the same thing with a diagram of a series circuit.
The meaning of "differently lighted up" is very unclear. As long as all the bulbs in a series circuit are connected to the circuit, and all of the bulbs have good filaments with no holes in them, current will flow in the circuit. Depending on the ratings of each bulb, the current may not be enough to cause all of them to glow visibly, but there will certainly be a current. That may or may not suit your definition of "work".
When light bulbs are turned on, they typically use up around 0.5 to 1 ampere of current.
Yes, a circuit with two light bulbs connected in series can light up. Current flows through the first light bulb, then through the second, allowing both bulbs to illuminate. If one bulb burns out, however, both bulbs will go out.
3 amps each
When two light bulbs are in place, there will be a circuit created where electricity can flow through both bulbs. If the circuit is intact and the bulbs are functioning, they will both light up. If one of the bulbs is faulty or the circuit is broken, then both bulbs may not light up.
Assuming the bulbs are identical, the voltage drop across each one is inversely proportional to the number of bulbs. So, for example, 240V could power 20 12V bulbs in series. In addition, the circuit would have to be able to supply the necessary current.
light up
In a parallel circuit with three bulbs, there are three separate pathways for current to flow, one for each bulb. This means that each bulb has its own independent connection to the power source, and if one bulb were to fail, the others would still light up.
In a parallel circuit, each component receives the same voltage, but if the bulbs are not compatible with the battery's voltage or if they are faulty, they may not light up. Additionally, if there is a short circuit or if the connections are improper, it can prevent the flow of current, resulting in no lights lighting up. Lastly, if the battery is depleted or has insufficient current capacity, it may not provide enough power for the bulbs to function.
Answer: it will burn out **Explain:**The same current flows through each part of a series circuit. If the circuit is broken at any point there won't be any current that will flow. In this case, if one of the bulbs blew out, the other bulb would not be able to light up because the flow of electric current would have been interrupted. #Carryonlearning
In a series circuit, all bulbs are necessary to complete the circuit. If one bulb goes out, the circuit is broken, so none of the bulbs would light up.
to limit the current and to use it as a back up battery capacitors are used ..