You have not provided enough information. For 12 volt peak to peak, purely AC signal, there will be no DC (hence purely AC). This means there is no offset - the AC signal peaks at 6 volts and -6 volts. The RMS value of this is VRMS = peak / sqrt(2) = 6 / 1.4.
The wave with the maximum RMS value, in comparision with the peak value, is the square wave.
From your description, this sounds like it is a sine wave offset to 10A, so the peak is at 20A, and the min is at 0? For this case, you have 10A DC (RMS) wave and a 10A Peak - neutral AC wave; The RMS value of the AC wave is: 10/2*sqrt(2) = 3.54A. So the RMS amplitude of this wave is 13.54A.
From your description, this sounds like it is a sine wave offset to 10A, so the peak is at 20A, and the min is at 0? For this case, you have 10A DC (RMS) wave and a 10A Peak - neutral AC wave; The RMS value of the AC wave is: 10/2*sqrt(2) = 3.54A. So the RMS amplitude of this wave is 13.54A.
The number of Joules (energy) is the same as dc provided the RMS values of the ac quantities are used.
When you say holdhold supply of 230volts, you are referring to the RMS value, not the peak value.
RMS current is converted to DC current by using a rectifier. Capacitors and other components are used to make a cleaner DC output with less ripple.
To convert DC values to AC values if you are wanting RMS values they are the same. 100V DC and 100V AC (RMS) are the same "value". If you want to know the Peak-To-Peak AC value you would multiply the RMS value by 1.414. So 100V AC RMS equals 141.4 V Peak to Peak.
The wave with the maximum RMS value, in comparision with the peak value, is the square wave.
RMS value is defined as "The amount of ac supply required to make same heat effect in resistor , which is made by dc current, in that resistor"
From your description, this sounds like it is a sine wave offset to 10A, so the peak is at 20A, and the min is at 0? For this case, you have 10A DC (RMS) wave and a 10A Peak - neutral AC wave; The RMS value of the AC wave is: 10/2*sqrt(2) = 3.54A. So the RMS amplitude of this wave is 13.54A.
The peak of a waveform that is purely sinusoidal (no DC offset) will be RMS * sqrt(2). This is the peak to neutral value. If you are looking for peak to peak, multiply by 2.
From your description, this sounds like it is a sine wave offset to 10A, so the peak is at 20A, and the min is at 0? For this case, you have 10A DC (RMS) wave and a 10A Peak - neutral AC wave; The RMS value of the AC wave is: 10/2*sqrt(2) = 3.54A. So the RMS amplitude of this wave is 13.54A.
Multiply the peak to neutral by .707 for a sine wave. The RMS value is the equivalent level available if it were DC, so it will always be lower than the peak value.
Peak voltage will be 1.414 times the RMS. Peak to Peak voltage, assuming no DC offset, will be 2 x 1.414 x the RMS value.
The number of Joules (energy) is the same as dc provided the RMS values of the ac quantities are used.
"Voltage peak" is generally used to denote the maximum(amplitude) of AC voltage supply. It can not be approximated as dc value. The closest approximation one can make for dc value of a ac supply is the RMS(root mean square) value of the voltage. So that the ohmic loss caused by the given AC voltage supply is equivalent to that caused by a dc supply having value equal to the RMS of this AC supply (for given impedance & time).
rms. dat means Vp-p will be 325V.