If the bulbs are in parallel, other bulbs aren't affected, so I guess you mean a series circuit.
A string of light bulbs connected in series (like a Christmas light string) connected to a specific supply voltage can be visualised as a string of rubber bands, knotted to each other in a line, and stretched to a specific distance.
If all the rubber bands are the same, they will all stretch equally, i.e. if all bulbs are the same, they will all have the same voltage across them.
Increasing the resistance of one bulb is like making one rubber band thinner than the others, and you can imagine what will happen.
The thin rubber band will stretch more than the others, and the others will take up the slack and become a bit shorter, i.e. the bulb with higher resistance will have more voltage across it, and the remaining bulbs will have slightly less than before.
The current (i.e. the tension in the string of rubber bands) reduces slightly.
Looking at the power dissipation for that light bulb, which is voltage x current, voltage will increase, and current will drop slightly, so the overall effect is that the bulb with the higher resistance will dissipate more power than the others.
It creates an extra load to the circuit if placed parallel to other circuits. this load approaches the equivalent of a short circuit as the resistance value placed there reduces.
The knot adds extra resistance and inductance to the wire, which in most cases will not make a difference to its performance in a normal circuit operating at dc or power supply frequencies.
That depends ... in a very interesting way ... on whether they are connected in series or in parallel. -- If the resistors are in series, then the total resistance increases when you add another resistor, and it's always greater than the biggest single one. -- If the resistors are in parallel, then the total resistance decreases when you add another resistor, and it's always less than the smallest single one.
If you add more batteries in series, the voltage would increase. This would drastically change the circuit. Normally this should also produce more current.The effect of adding more batteries in parallel is insignificant for many circuits. Adding more batteries in parallel is like lowering a battery's internal resistance - which, for many circuits, can be neglected.Example: The battery's internal resistance can be neglected; the battery gives a voltage of 12 volt, you connect it to a resistance of 2 ohm. According to Ohm's law, that will give you a current of 6 ampere. Note that the battery capacity does not enter the calculation! Adding a second battery (of the same kind) will produce the same voltage, thus, the same current.If you add more batteries in series, the voltage would increase. This would drastically change the circuit. Normally this should also produce more current.The effect of adding more batteries in parallel is insignificant for many circuits. Adding more batteries in parallel is like lowering a battery's internal resistance - which, for many circuits, can be neglected.Example: The battery's internal resistance can be neglected; the battery gives a voltage of 12 volt, you connect it to a resistance of 2 ohm. According to Ohm's law, that will give you a current of 6 ampere. Note that the battery capacity does not enter the calculation! Adding a second battery (of the same kind) will produce the same voltage, thus, the same current.If you add more batteries in series, the voltage would increase. This would drastically change the circuit. Normally this should also produce more current.The effect of adding more batteries in parallel is insignificant for many circuits. Adding more batteries in parallel is like lowering a battery's internal resistance - which, for many circuits, can be neglected.Example: The battery's internal resistance can be neglected; the battery gives a voltage of 12 volt, you connect it to a resistance of 2 ohm. According to Ohm's law, that will give you a current of 6 ampere. Note that the battery capacity does not enter the calculation! Adding a second battery (of the same kind) will produce the same voltage, thus, the same current.If you add more batteries in series, the voltage would increase. This would drastically change the circuit. Normally this should also produce more current.The effect of adding more batteries in parallel is insignificant for many circuits. Adding more batteries in parallel is like lowering a battery's internal resistance - which, for many circuits, can be neglected.Example: The battery's internal resistance can be neglected; the battery gives a voltage of 12 volt, you connect it to a resistance of 2 ohm. According to Ohm's law, that will give you a current of 6 ampere. Note that the battery capacity does not enter the calculation! Adding a second battery (of the same kind) will produce the same voltage, thus, the same current.
They will dim because you have more resistance in the circuit. More resistance means less current which means less light. The power is P=V*I = I/R*I = I²/R Think of blowing through one straw. Now attach a second straw end on with no leaks between joints and then attach a third straw in a long line. Which one is the easiest to blow?
If the bulbs are in a series circuit the voltage drops at each bulb drops as additional bulbs are added. In a parallel circuit the voltage is constant no matter how many bulbs are added.
Increasing voltage leads to an increase in the electric field strength, which in turn increases the kinetic energy of charged particles moving through the circuit. This higher kinetic energy results in an increase in the overall energy of the system.
It creates an extra load to the circuit if placed parallel to other circuits. this load approaches the equivalent of a short circuit as the resistance value placed there reduces.
Adding an extra shot of espresso to a coffee drink increases the strength and intensity of the flavor, providing a more robust and concentrated caffeine boost.
The knot adds extra resistance and inductance to the wire, which in most cases will not make a difference to its performance in a normal circuit operating at dc or power supply frequencies.
extra resistance is added in order to decrease starting current and improve starting torque
That depends ... in a very interesting way ... on whether they are connected in series or in parallel. -- If the resistors are in series, then the total resistance increases when you add another resistor, and it's always greater than the biggest single one. -- If the resistors are in parallel, then the total resistance decreases when you add another resistor, and it's always less than the smallest single one.
A: Adding any resistance bulbs or whatever in a series circuit will reduce current and will reduce total power. In this case the bulb will glow dimmer as any additional bulbs are placed in the series circuit. this is true if the same input source is kept constant.
The voltmeter has an internal resistance, which should be as high as possible. As this resistance draws current from the circuit under test, it will affect circuit operation. This is more pronounced in a high impedance circuit because the current drawn flows through higher resistances.
If you add more batteries in series, the voltage would increase. This would drastically change the circuit. Normally this should also produce more current.The effect of adding more batteries in parallel is insignificant for many circuits. Adding more batteries in parallel is like lowering a battery's internal resistance - which, for many circuits, can be neglected.Example: The battery's internal resistance can be neglected; the battery gives a voltage of 12 volt, you connect it to a resistance of 2 ohm. According to Ohm's law, that will give you a current of 6 ampere. Note that the battery capacity does not enter the calculation! Adding a second battery (of the same kind) will produce the same voltage, thus, the same current.If you add more batteries in series, the voltage would increase. This would drastically change the circuit. Normally this should also produce more current.The effect of adding more batteries in parallel is insignificant for many circuits. Adding more batteries in parallel is like lowering a battery's internal resistance - which, for many circuits, can be neglected.Example: The battery's internal resistance can be neglected; the battery gives a voltage of 12 volt, you connect it to a resistance of 2 ohm. According to Ohm's law, that will give you a current of 6 ampere. Note that the battery capacity does not enter the calculation! Adding a second battery (of the same kind) will produce the same voltage, thus, the same current.If you add more batteries in series, the voltage would increase. This would drastically change the circuit. Normally this should also produce more current.The effect of adding more batteries in parallel is insignificant for many circuits. Adding more batteries in parallel is like lowering a battery's internal resistance - which, for many circuits, can be neglected.Example: The battery's internal resistance can be neglected; the battery gives a voltage of 12 volt, you connect it to a resistance of 2 ohm. According to Ohm's law, that will give you a current of 6 ampere. Note that the battery capacity does not enter the calculation! Adding a second battery (of the same kind) will produce the same voltage, thus, the same current.If you add more batteries in series, the voltage would increase. This would drastically change the circuit. Normally this should also produce more current.The effect of adding more batteries in parallel is insignificant for many circuits. Adding more batteries in parallel is like lowering a battery's internal resistance - which, for many circuits, can be neglected.Example: The battery's internal resistance can be neglected; the battery gives a voltage of 12 volt, you connect it to a resistance of 2 ohm. According to Ohm's law, that will give you a current of 6 ampere. Note that the battery capacity does not enter the calculation! Adding a second battery (of the same kind) will produce the same voltage, thus, the same current.
bulk oil circuit breaker
They will dim because you have more resistance in the circuit. More resistance means less current which means less light. The power is P=V*I = I/R*I = I²/R Think of blowing through one straw. Now attach a second straw end on with no leaks between joints and then attach a third straw in a long line. Which one is the easiest to blow?