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Power Factor ranges from zero to one. Watts which is a measure of the work being done is Volts x Amps x PF. As you can see it is most efficient to have a PF = 1. The PF is the measure by which the current waveform is out of phase with voltage waveform. They are in phase for a pure resistive load and deteriorates with inductive loads like motors.
What else can I help you with?
Why does the terminal voltage increase in leading load?
due to decrease in power factor
Why it is not correct to say that potential difference is the work done in moving unit charge between the point concerned?
Voltage is defined as potential difference (units of volts). Work is equivalent to power (over time), and its' unit is joules. Power is equivalent to the potential difference times the current flow. Without current flow, there is no power, so it is incorrect to define potential difference as work. What I think you're implying is potential energy and potential difference are the same: Potential energy of a rock can be increased by raising the rock into the air. The increase of potential energy of the rock is equivalent to the real work done to raise it higher into the air. This is a true statement. Potential energy (joules) and potential difference (volts) are not equivalent, though, since potential differenence is not defined as work.
Does raising the power factor of a residence result in dollar savings on your electric bill?
No. Your energy meter monitors the supply voltage and the in-phase component of the load current, so improving your power factor will have no effect on your energy consumption and, therefore, your electricity bill.
What is 3dB and 6dB?
3dB and 6dB are terms used in audio and signal processing to describe changes in power levels. A change of 3dB typically represents a power increase or decrease by a factor of two; for example, doubling the power results in a 3dB increase. Similarly, a change of 6dB indicates a power change by a factor of four, meaning that quadrupling the power results in a 6dB increase. These measurements are logarithmic and help quantify the relative strength of signals or sound levels.
What is the harmonic factor in a power system?
Two factors reduce the power used by a piece of equipment compared to the volt-amps drawn from the supply: power factor and harmonic factor. Both factors increase the power transmission losses incurred in supplying a given amount of power.The power factor is less than 1 when voltage and current are out of phase with each other.When they are in phase the power equals the volt-amps except for a nonlinear load with a current that is not proportional to voltage. This generates harmonics in the current and the effect is that the power is less than the volt-amps, by an amount equal to the harmonic factor.
How will an increase in amplitude and power affect dB?
The decibel (dB) scale is logarithmic. An increase of power by a factor of 10 is an increase of +10 dB. If power increases by a factor of 100, that is equivalent to +20 dB.The decibel (dB) scale is logarithmic. An increase of power by a factor of 10 is an increase of +10 dB. If power increases by a factor of 100, that is equivalent to +20 dB.The decibel (dB) scale is logarithmic. An increase of power by a factor of 10 is an increase of +10 dB. If power increases by a factor of 100, that is equivalent to +20 dB.The decibel (dB) scale is logarithmic. An increase of power by a factor of 10 is an increase of +10 dB. If power increases by a factor of 100, that is equivalent to +20 dB.
If we increase the current then what about the power factor?
The power factor depends on the phase angle between the voltage and current on a conductor. The amplitude of the current has no effect on it.
Does a increase in current limit result in increase in electrical consumption?
Not necessarily. If a load has a low power factor, it will be drawing more current than necessary, but its energy consumption will be no different from it having a high power factor.
How do you increase voltage in a generator?
At least to a certain extent, by increasing the field current. Or In Real Power Plant they decrease the power factor to increase the voltage.
Why does the terminal voltage increase in leading load?
due to decrease in power factor
How can a society increase its potential output?
a society can increase its potential as follow 1 increase in productivity 2 increase in investment 3 inprove on man-power development
How is raising a quotient to a power similar to raising a product to a power?
You are both raising the factors or numerator and denominator
How many watts is 10kva?
Watts is equal to volts x current x Power Factor. The maximum value of Power Factor is 1 for a resistive load. For motors and other inductive devices the Power Factor is less than 1. Your maximum wattage is 10,000 watts and decreases as Power Factor decreases.
Why it is not correct to say that potential difference is the work done in moving unit charge between the point concerned?
Voltage is defined as potential difference (units of volts). Work is equivalent to power (over time), and its' unit is joules. Power is equivalent to the potential difference times the current flow. Without current flow, there is no power, so it is incorrect to define potential difference as work. What I think you're implying is potential energy and potential difference are the same: Potential energy of a rock can be increased by raising the rock into the air. The increase of potential energy of the rock is equivalent to the real work done to raise it higher into the air. This is a true statement. Potential energy (joules) and potential difference (volts) are not equivalent, though, since potential differenence is not defined as work.
Why it is not correct to say that the potential difference is the work done in moving charge between the points concerned?
Voltage is defined as potential difference (units of volts). Work is equivalent to power (over time), and its' unit is joules. Power is equivalent to the potential difference times the current flow. Without current flow, there is no power, so it is incorrect to define potential difference as work. What I think you're implying is potential energy and potential difference are the same: Potential energy of a rock can be increased by raising the rock into the air. The increase of potential energy of the rock is equivalent to the real work done to raise it higher into the air. This is a true statement. Potential energy (joules) and potential difference (volts) are not equivalent, though, since potential differenence is not defined as work.
Does raising the power factor of a residence result in dollar savings on your electric bill?
No. Your energy meter monitors the supply voltage and the in-phase component of the load current, so improving your power factor will have no effect on your energy consumption and, therefore, your electricity bill.
What effect do var's have on the power factor of the circuit?
VAr is reactive power, caused by either inductive or capacitive loads. The ideal power factor to have is 1, anything less than that is a loss on the network. The effect of VArs on the circuit though depends. If you have a load that is mainly inductive, then adding more inductive reactance will lower the power factor. However, if you introduce capacitive reactance this will increase the power factor, and the opposite is true if its a mainly capacitive circuit. So VArs will either increase or decrease the power factor depending on the load of the circuit. The ideal situation is to balance inductive reactance with capacitive reactance so they in effect cancel each other out and power factor is 1.
