it the ratio of load applied on the displacement of spring.. stiffness=load/change in length.
You need a spring scale machine, as commonly found in the aircraft industry.
the stiffness of a vehicle structure in a crash
In my opinion, Least count of Spring Balance is very less to measure valuable metal like Gold.
i dont know but it has 10 letters :) im doing a crossword for science and they asked that question but I cant figure it out this is halohayd the answer is hardness
by smith hammer
The stiffness of a spring can be measured by calculating its spring constant, which is the force required to deform the spring by a certain distance. This can be done by applying a known force to the spring and measuring the resulting displacement, then using Hooke's Law (F = kx) to determine the spring constant. Another method is to measure the frequency of oscillation of the spring when subjected to a known mass, as the stiffness is inversely proportional to the period squared.
The spring constant value of the system is a measure of the stiffness of the spring and how much force is needed to stretch or compress it.
The value of the spring constant in this system is a measure of the stiffness of the spring and determines how much force is needed to stretch or compress the spring by a certain distance.
If the length of a spring is halved, the stiffness remains the same. Stiffness of a spring is determined by its material and construction, not by its length. Cutting the length in half does not change the material properties that govern stiffness.
If a spring is cut in half, its stiffness, or spring constant (k), will effectively double. This is because the stiffness of a spring is inversely related to its length; a shorter spring can resist deformation more effectively when a force is applied. Therefore, each half of the original spring will have twice the stiffness of the full spring.
The constant spring stiffness formula is the force applied to the spring equal to the stiffness times the distance it moved. F=kx. Depending on where your axis are, it could be negative.
Increasing the spring stiffness will result in a higher natural frequency. This is because a stiffer spring will require more force to displace it, leading to faster oscillations and a higher frequency. Conversely, decreasing the spring stiffness will lower the natural frequency of the system.
a helical spring has N turns of coil of diameter D, and a second spring made of same material and of same wire diameter has N/2 turns of coil of diameter 2D. if stiffness of first spring is k, then stiffness of second spring is
Spring stiffness is a property that relates load to deflection. Let k = stiffness and P = load and x = deflection, then P = kx The stiffer the spring, k, the smaller the deflection under a constant load. k can be measured for springs and otherdevices, such as beams, with simple load deflection devices or machines that measure deflection as function of laod
To determine the stiffness of a spring using a rectangular footing, you can apply a known load to the footing and measure the resulting deflection. The stiffness (k) can be calculated using Hooke's Law, expressed as ( k = \frac{P}{\delta} ), where ( P ) is the applied load and ( \delta ) is the measured deflection. Ensure that the setup is stable and that the load is applied uniformly to obtain accurate results. This method provides an effective way to evaluate the spring's stiffness under realistic conditions.
The strength of a spring is a force and therefore is measured in units such as newtons or pounds. Many cylindrical springs, for example, produce various forces at different lengths making it necessary to indicate the lengths at which the forces have been measured.
To find the compression of a spring, you can use the formula: Compression Force applied / Spring constant. The compression is the distance the spring is pushed or squeezed from its original position when a force is applied to it. The spring constant is a measure of the stiffness of the spring. By dividing the force applied by the spring constant, you can determine how much the spring is compressed.