first calculate current from power and voltage.
then since wire comes in standard gauges with a maximum current rating for each just select the wire gauge from the table that can carry more current than the value calculated.
380V ÷ √3 = 219.4
To calculate the outer diameter (OD) of a cylindrical object when you have the inner diameter (ID) and the thickness of the material, you can use the formula: OD = ID + 2 × Thickness. This accounts for the thickness on both sides of the cylinder. Simply add twice the thickness to the inner diameter to get the outer diameter.
Divide the watts by the voltage to get current (amps). 60W / 250V = about 1/4 Amp.
By Ohm's Law.... Voltage equals Current times Resistance (V=I*R) So if given the voltage and resistance of a system and applying algebra I=V/R .
The effect of diode voltage drop as the output voltage is that the input voltage will not be totally transferred to the output because power loss in the diode . The output voltage will then be given by: vout=(vin)-(the diode voltage drop).
the given kw Divide by the your voltage
380V ÷ √3 = 219.4
if an equation is given the correct answer, it is mathematically correct.
P = E * I Power (watts) equals voltage (E) times current (I)
Rated voltage is the voltage at primary side. Rated current can be found from the equation, Rated Current= Output KVA / Output rated voltage
The potential energy voltage equation used to calculate the electrical potential energy stored in a system is given by the formula: Potential Energy Charge x Voltage.
You can't do that calculation given only that data. It depends more on the design of the LED than its drive levels.
P = I^2 R = IV = v^2 / R , Where P is power, I is current, R is resistance, and V is voltage. Given voltage and current, power = current * voltage, or P = IV.
The electric field voltage equation is E V/d, where E is the electric field strength, V is the voltage, and d is the distance between the charges. To calculate the electric field strength at a given point in space, you can use this equation by plugging in the values of voltage and distance to find the electric field strength.
This is a voltage drop question. To answer this type of question a circuit voltage and the circuit load amperage must be given to calculate an answer.
To calculate the voltage, you need to know the current (amperage) as well. The formula to calculate power (watts) given voltage (volts) and current (amps) is: Power (P) = Voltage (V) x Current (I). Without knowing the current, it is not possible to directly convert watts to volts.
To calculate the wattage of a device, you need to know both the current (in amperes) and the voltage (in volts). If the voltage is not provided, you cannot accurately calculate the wattage. In this case, with only the current (4 A) given, you cannot determine the wattage without knowing the voltage as well.