No way of knowing w/o knowing the voltage.
It depends on the wattage the fan draws. A simple way to work it out is to use a simple formula. Find where it tells you the wattage and then devide by the house hold voltage and that will give you how much current is being used in amps
The formula you are looking for is W = A x V. Watts = Amps x Volts.
Different appliances have different wattage draws. Without knowing the wattage of the appliance, an answer can not be given.
No, a higher wattage INCANDESCENT light bulb uses more current than a lower wattage INCANDESCENT light bulb. Some CF and LED bulbs are rated by the amount of light that an incandescent bulb would produce, but they are also rated by the wattage that they use.
To answer this question the wattage of the block heater must be stated. Amps = Watts/Volts.
The wattage of the drill can be calculated by multiplying the voltage (120 V) by the current (4 A). Wattage = Voltage x Current Wattage = 120 V x 4 A = 480 watts. Therefore, the wattage of the drill is 480 watts.
It depends on the wattage the fan draws. A simple way to work it out is to use a simple formula. Find where it tells you the wattage and then devide by the house hold voltage and that will give you how much current is being used in amps
The formula you are looking for is W = A x V. Watts = Amps x Volts.
(current * voltage) / psu efficiency (5 amps * 19 volt) / ~0.8 = ~118 watts
Different appliances have different wattage draws. Without knowing the wattage of the appliance, an answer can not be given.
No, a higher wattage INCANDESCENT light bulb uses more current than a lower wattage INCANDESCENT light bulb. Some CF and LED bulbs are rated by the amount of light that an incandescent bulb would produce, but they are also rated by the wattage that they use.
To answer this question the wattage of the block heater must be stated. Amps = Watts/Volts.
The amps it draws depends on how big it is. Typically 2-12 amps. Check for a manufacturer's plate that shows the wattage Most of the load in a rice cooker is a resistive heating element, so the amperage will be quite close to the wattage divided by the voltage (220 here).
The inverter draws little current on its own. It is the load that is connected to the inverter. If there were no load on the inverter you could use an ampmeter to determine the no load current. One thing to consider is that a higher wattage inverter would have larger gauge wire which is of lower resistance. This could make the no load current lower for the higher wattage inverter. Bottom line is you would have to measure or have a specification on the no load current.
Power = Voltage x Current P=V.I Power (in Watts) = 110V x 8.70A = 957W (Appx. 1kW) - Neeraj Sharma
Usually a CFL has two ratings. The first is wattage and the second is in mA I suspect the wattage is only the wattage of the bulb itself and the second is the actual current draw of both the light bulb and the ballast. They are not compatible. If you figure the mA and multiply times the voltage you will obtain close to the actual wattage of the combination of the bulb and the ballast. I have a 100 watt Feit BPESL25T which indicates it draws 25 Watts when it actually draws 47.5 Watts. Very close to the mA (400 x 120 VAC =48 Watts) indicated on the base. Almost all CFLs I've tested with my very accurate Fluke RMS meter draw twice the wattage they indicate. Not such a good deal.
A 60 watt light bulb typically draws 0.5 amps from a 120-volt power source. This is calculated by dividing the wattage (60 watts) by the voltage (120 volts).