The voltage and current will give the kVA, but the kW depends on the power factor of whatever load is connected to the supply.
For a (let's say) 11 kV supply, the voltage from line to neutral is 11,000/sqrt(3) which is 6351 v. The kVA on each phase is 6.351 times the current, and you just add up the three kVA values to find the total.
At higher voltges like 11 kV the three currents in the lines are usually very nearly equal.
You have to know the power loading and phase angle (or power factor) between each pairh of the phases, otherwise you could be making serious errors.
96 kW means 32 kW from each phase. If the load is star connected each resistor has 277 volts across it and carries 32,000/277 amps, 115.5 amps. The load resistors are 277/115.5 ohms or 2.40 ohms If the load is delta connected each resistor has 480 volts across it and carries 66.7 amps. The load resistors are 480/66.7 ohms or 7.20 ohms. In both cases the line current is 115.5 amps.
For practical purposes, transformers do not lose power during transformation. Thus, if you have the VA of the transformer, you can simply divide the VA by the voltage to get a rough idea of maximum current. In a real application, the maximum amperage will be dependent on the phase angle of the transformer.
You can't measure an RLA. It is determined by the factory that manufactured the compressor. To answer your other question, a 230 volt load is actually using both legs as part of the circuit, so you can measure either leg with a current meter but there is no need to add them up.
A 7.5 kW three phase load will be balanced by the manufacturer. When connected to a three phase source the line current on each phase will be equal.
Measuring the current in each phase (or do you mean 'line'?) will not give you sufficient information to work out what you are asking for.
Still 30 amps, but at 240 V you'll have twice the watts that you would on a 120 V, 30 amp circuit, and after all, watts are what actually does the work.
In a three-phase 225 amp panelboard, each phase will carry 225 amps. This means that the total current flowing through the panelboard is distributed evenly across the three phases, allowing for a maximum of 225 amps on each phase at a time.
In a standard 3 phase system in North America, 7kVa would be equivalent to 19.5 amps on each phase. The equation is: 7kva*1000/208v/1.73=19.45 amps (3 phase)
In a three phase 225 amp panel, there would be a total of 225 amps available for each phase, making it a total of 675 amps for all three phases combined. This means that you could have up to 225 amps of current flowing through each phase simultaneously.
Assuming it is a 208-volt line voltage (as normal in 3-phase) the phase voltage is that divided by sqrt(3), or 120 volts. Each phase has to supply 10 kW so the current on each phase is 83.3 amps.
Yes, for a 15HP 3-phase 415V AC motor, each phase will draw approximately 26 Amps of current when running under normal operating conditions. This results in a total current draw of 26 Amps per phase for the motor.
Each hot leg to the neutral wire of the service has the ampacity of 200 amps, that is why 3/0 wire is required. A 3/0 copper wire with an insulation factor of 90 degrees C is rated at 210 amps.
For a single phase circuit, the equation you are looking for is I = W/E. Amps = Watts/Volts.
thong each wire using amp meter
On a 50 amp 3 phase connector, you can pull 50 amps per leg. This means that each of the three phases can carry up to 50 amps individually, resulting in a total capacity of 50 amps per leg.
You have to know the power loading and phase angle (or power factor) between each pairh of the phases, otherwise you could be making serious errors.