Divide 25,000 by the supply voltage to get the current.
The electric heater is basically a resistor, designed to have the right resistance to draw the required current. So a 2 kW heater designed for a 230 v supply is really a resistor of 28.8 ohms, so when it's connected the current is 8 amps and the power is 2 kW.
Current (amps)=Watts/Volts =2000/120 =16.75 =16.75 amps
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draw a line chart.
Draw thewaveform of AM signal and DSBSV
Assuming it is a 208-volt line voltage (as normal in 3-phase) the phase voltage is that divided by sqrt(3), or 120 volts. Each phase has to supply 10 kW so the current on each phase is 83.3 amps.
The formula you are looking for is I = W/E.
Using the formula Power = Voltage x Current, we can calculate the current: Current = Power / Voltage. Plugging in the values, we get 1500W / 120V = 12.5A. So, a 1500W resistance heater would draw 12.5A of current at 120V.
Watts is the amount of power the heater has and amps would be the draw- if it is a 120 volt heater than the amps would be 12.5 amps and it is instantaneous
To calculate the amperage drawn by the heater, you can use the formula: Amperage (A) = Power (W) / (Voltage (V) * Square root of 3). In this case, the amperage drawn will be approximately 5.8 Amps.
NOPE
Watts = Amps x Volts for a resistive load like a water heater.
To calculate the amperage draw, you can use the formula P = V x I, where P is the power in watts, V is the voltage in volts, and I is the current in amps. Given that the power is 1200 watts and voltage is 120 volts, you can rearrange the formula to solve for current. Therefore, I = P / V, so the amperage draw of the heater would be 10 amps.
To answer this question the voltage of the heater must be given. I = W/E.
A ruler or straight edge.
4.12A. V=IR
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