In Java, all arrays have a finite size. Even if you did not initialize an array to a particular size (say the array was being passed into a method), some other part of the program did. Because of this, the length of an array can always be accessed via the .length parameter.
Example:
int[] arr = new int[5];
System.out.print(arr.length); //5
public void k(int[] arr)
{
System.out.print(arr.length) //arr will always have a finite size
}
To calculate the size of array the type of array should be given. Ex: if it is of integer type that means int arr[100] and integer is of 4 bytes, then the size of array will be 400 bytes.
An irregular dimensional array is a special type of multi-dimensional array.First we must understand that a multi-dimensional array is just an array of arrays. Each element in the array is, itself, an array of elements.A regular multi-dimensional array will be an array of size n, with each element containing a separate array of size m. That is, each sub-array has the same size.An irregular multi-dimensional array will be a multi-dimensional array in which each sub-array does not contain the same number of elements.Regular array:array[0] = new array{0, 1, 2}array[1] = new array{3, 4, 5}array[2] = new array{6, 7, 8}array[3] = new array{9, 10, 11}This regular array is an array of size 4 in which each sub-array is of size 3.Irregular array:array[0] = new array{0, 1, 2}array[1] = new array{3, 4}array[2] = new array{5, 6, 7}array[3] = new array{8, 9, 10, 11}This irregular array is an array of size 4 in which the size of each sub-array is not the same.
sparse array is one which has contents lower than its maximum size, that is the array has free or empty locations....
It's not exactly true. Array with fixes size are efficient, but do not work well when you have to resize your array. This actually is the answer for your question. Fixed size arrays are not efficient if you have to change the size. Also you cannot destroy them and release memory used to save the array (for that you have to use operator new).
Use a pointer... int a*; a = malloc(sizeof(int)*100); //allocate space for 100 elements free(a); a = malloc(sizeof(int)*1000); // allocate space for 1000 elements free(a);
To calculate the size of array the type of array should be given. Ex: if it is of integer type that means int arr[100] and integer is of 4 bytes, then the size of array will be 400 bytes.
#include "stdio.h" #define SIZE 100; void main() { int array[SIZE], i, size; printf("\nEnter the Size off Array :- "); scanf("%d", &size); printf("\nEnter the Elements of Array :- ")' for(i = 0; i < size; i++) scanf("%d", &array[i]; printf("\nThe Elements of entered Array :- "); for(i = 0; i < size; i++) printf("%7d", array[i]); }
To get the size of an array in C, you can use the sizeof() operator. This operator returns the number of bytes occupied by the array, so to get the number of elements in the array, you can divide the total size by the size of one element.
! variable to declase the size of an array in True Basic ! set up a dummy value for array - any initial value > 0 is fine. DIM array$(999) ! ask the user for the length of the array INPUT PROMPT "Enter array size " :size ! resize the array with user defined length MAT REDIM array$(size) ! program end END
void bubblesort (int* array, int size) { if (!array size<2) return; int last_swap = size; while (last_swap>0) { int n=last_swap; for (int i=1; i<last_swap; ++i) { if (array[i]<array[i-1]) { array[i]^=array[i-1]^=array[i]^=array[i-1]; n=i; } last_swap = n; } }
An irregular dimensional array is a special type of multi-dimensional array.First we must understand that a multi-dimensional array is just an array of arrays. Each element in the array is, itself, an array of elements.A regular multi-dimensional array will be an array of size n, with each element containing a separate array of size m. That is, each sub-array has the same size.An irregular multi-dimensional array will be a multi-dimensional array in which each sub-array does not contain the same number of elements.Regular array:array[0] = new array{0, 1, 2}array[1] = new array{3, 4, 5}array[2] = new array{6, 7, 8}array[3] = new array{9, 10, 11}This regular array is an array of size 4 in which each sub-array is of size 3.Irregular array:array[0] = new array{0, 1, 2}array[1] = new array{3, 4}array[2] = new array{5, 6, 7}array[3] = new array{8, 9, 10, 11}This irregular array is an array of size 4 in which the size of each sub-array is not the same.
Awais khanLOC(LA[K]) =base(LA)+w(k-lowerbound)
To double the size of an array efficiently, you can create a new array with double the capacity, copy the elements from the original array to the new array, and then update the reference to the original array to point to the new array. This process ensures that the array is resized without having to individually resize each element.
Ah, honey, in C, you can get the number of elements in an array by dividing the total size of the array by the size of one element. So, if you have an array of integers, you can do something like int size = sizeof(array) / sizeof(array[0]); and voilà, you've got the number of elements. Just be careful with those pesky pointers and make sure you're not trying to count elements in a pointer instead of an actual array.
sparse array is one which has contents lower than its maximum size, that is the array has free or empty locations....
It's not exactly true. Array with fixes size are efficient, but do not work well when you have to resize your array. This actually is the answer for your question. Fixed size arrays are not efficient if you have to change the size. Also you cannot destroy them and release memory used to save the array (for that you have to use operator new).
2D array of size 2x8 and 1D array of size 16