To get the size of an array in C, you can use the sizeof() operator. This operator returns the number of bytes occupied by the array, so to get the number of elements in the array, you can divide the total size by the size of one element.
To determine the size of an array in C using the keyword sizeof, you would use the syntax: sizeof(array) / sizeof(array0).
Ah, honey, in C, you can get the number of elements in an array by dividing the total size of the array by the size of one element. So, if you have an array of integers, you can do something like int size = sizeof(array) / sizeof(array[0]); and voilà, you've got the number of elements. Just be careful with those pesky pointers and make sure you're not trying to count elements in a pointer instead of an actual array.
To double the size of an array efficiently, you can create a new array with double the capacity, copy the elements from the original array to the new array, and then update the reference to the original array to point to the new array. This process ensures that the array is resized without having to individually resize each element.
An array is not a derived data type at all. In order to be derived there has to be a base class and an array has no base class. Here is the basic declaration of the std::array template class from the <array> header file: template<class _Ty, size_t _Size> class array { // fixed size array of values // ... }; A vector, on the other hand, is derived (from the <vector> header file): template<class _Ty, class _Alloc = allocator<_Ty>> class vector : public _Vector_alloc<!is_empty<_Alloc>::value, _Vec_base_types<_Ty, _Alloc>> { // varying size array of values // ... };
The time complexity of an algorithm that uses a binary search on a sorted array is O(log n), where n is the size of the input array.
#include main() { int array[100], minimum, size, c, location = 1; printf("Enter the number of elements in array\n"); scanf("%d",&size); printf("Enter %d integers\n", size); for ( c = 0 ; c < size ; c++ ) scanf("%d", &array[c]); minimum = array[0]; for ( c = 1 ; c < size ; c++ ) { if ( array[c] < minimum ) { minimum = array[c]; location = c+1; } } printf("Minimum element is present at location number %d and it's value is %d.\n", location, minimum); return 0; }
To determine the size of an array in C using the keyword sizeof, you would use the syntax: sizeof(array) / sizeof(array0).
Platform-dependent.
Ah, honey, in C, you can get the number of elements in an array by dividing the total size of the array by the size of one element. So, if you have an array of integers, you can do something like int size = sizeof(array) / sizeof(array[0]); and voilà, you've got the number of elements. Just be careful with those pesky pointers and make sure you're not trying to count elements in a pointer instead of an actual array.
Your best bet would probably be to iterate through the array using a for loop and compare each value to the current low and high values (which you would store in a local variable) for example: for each element in array { if current is less than lowest_value lowest_value = current else if current is greater than highest_value highest_value = current }
Platform-dependent.
Basically in c++ passing an array as an argument only provides a pointer to the first value and that function won't know how many values it has.If you read beyond the size you will just get garbage from memory.
Generally, a array is fixed in size. With some libraries, however, they are extensible, either by reallocation/copying strategies (C/C++/STL), or by linking/referencing strategies (JAVA).
Heres something i whipped up in a hurry... This uses the Bubble Sort method found (related links) #include <iostream> using namespace std; int main(int argc, const char* argv) { int arraysize = 5; //Unsorted array size int array [] = { 5, 3, 4, 2, 1 }; //The array of numbers itself //Display the unsorted array cout << "Before: {"; for (int c=0; c <= arraysize; c++) { cout << array[c]; if (c != arraysize) { cout << ","; } } cout << "}" << endl; //Acctually sort the array int tmp=0; //Used for swaping values for (int loop=0; loop <= (arraysize - 1); loop++) { for (int c=0; c <= (arraysize - 1); c++) //The sort loop { if (array[c] > array[c + 1]) { //Swaps the two values in the array tmp = array[c]; array[c] = array[c + 1]; array[c + 1] = tmp; //Cleanup tmp = 0; } } } //Display the sorted array cout << "After: {"; for (int c=0; c <= arraysize; c++) { cout << array[c]; if (c != arraysize) { cout << ","; } } cout << "}" << endl; return 0; }
#include "stdio.h" #define SIZE 100; void main() { int array[SIZE], i, size; printf("\nEnter the Size off Array :- "); scanf("%d", &size); printf("\nEnter the Elements of Array :- ")' for(i = 0; i < size; i++) scanf("%d", &array[i]; printf("\nThe Elements of entered Array :- "); for(i = 0; i < size; i++) printf("%7d", array[i]); }
in c simply add three lines in the begining of your program: int x; printf("enter the size of the array to be entered :"); scanf("%d",&x); after that use x as your maximum limit of array in your program. in c++ just replace above printf & scanf statements by cout<<"enter the size of the array to be entered :"; & cin>>x; respectively and do not use brackets.
No. An array is a collection of objects of any type, such as doubles, not just characters. You can even have arrays of arrays, or arrays of structs. In C, the size of an array is fixed, but it is possible to write code that will allow you to manually make it variable in size.