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What is the Maximum limit of array size in c language?
Platform-dependent.
How can I get the size of an array in C?
To get the size of an array in C, you can use the sizeof() operator. This operator returns the number of bytes occupied by the array, so to get the number of elements in the array, you can divide the total size by the size of one element.
What is sparce array?
sparse array is one which has contents lower than its maximum size, that is the array has free or empty locations....
How you get the size of arrays from user?
in c simply add three lines in the begining of your program: int x; printf("enter the size of the array to be entered :"); scanf("%d",&x); after that use x as your maximum limit of array in your program. in c++ just replace above printf & scanf statements by cout<<"enter the size of the array to be entered :"; & cin>>x; respectively and do not use brackets.
C program to copy one matrix to another matrix?
#include main() { int array[100], minimum, size, c, location = 1; printf("Enter the number of elements in array\n"); scanf("%d",&size); printf("Enter %d integers\n", size); for ( c = 0 ; c < size ; c++ ) scanf("%d", &array[c]); minimum = array[0]; for ( c = 1 ; c < size ; c++ ) { if ( array[c] < minimum ) { minimum = array[c]; location = c+1; } } printf("Minimum element is present at location number %d and it's value is %d.\n", location, minimum); return 0; }
What is the syntax for determining the size of an array in C using the keyword sizeof?
To determine the size of an array in C using the keyword sizeof, you would use the syntax: sizeof(array) / sizeof(array0).
How can I get the number of elements in an array in C?
Ah, honey, in C, you can get the number of elements in an array by dividing the total size of the array by the size of one element. So, if you have an array of integers, you can do something like int size = sizeof(array) / sizeof(array[0]); and voilà, you've got the number of elements. Just be careful with those pesky pointers and make sure you're not trying to count elements in a pointer instead of an actual array.
How do you find the minimum value of an array in c language?
Your best bet would probably be to iterate through the array using a for loop and compare each value to the current low and high values (which you would store in a local variable) for example: for each element in array { if current is less than lowest_value lowest_value = current else if current is greater than highest_value highest_value = current }
Write a c program to find the maximum value of 25 element in an array?
int findMax(int *array) { int max = array[0]; for(int i = 1; i < array.length(); i++) { if(array[i] > max) max = array[i] } return max; }
Why should a function that accepts an array as an argument and processes that array also accept an argument specifying the array?
Basically in c++ passing an array as an argument only provides a pointer to the first value and that function won't know how many values it has.If you read beyond the size you will just get garbage from memory.
Write a c program to find the maximum of two numbers and print out with its position?
maxValue = function (array) {mxm = array[0];for (i=0; i<array.length; i++) {if (array[i]>mxm) {mxm = array[i];}}return mxm;}; i don't know
Is the array size is fixed after it is created?
Generally, a array is fixed in size. With some libraries, however, they are extensible, either by reallocation/copying strategies (C/C++/STL), or by linking/referencing strategies (JAVA).
