To check a mobile number, you can verify it by calling or texting the number to see if it is active. Additionally, you can use online services or apps that provide reverse phone lookup features to obtain information about the number. If you need to confirm ownership, asking the person directly or using social media profiles linked to the number can also help. Always ensure you respect privacy and legal guidelines when checking someone's mobile number.
/*Program to find whether given no. is Armstrong or not. Example : Input - 153 Output - 1^3 + 5^3 + 3^3 = 153, so it is Armstrong no. */ class Armstrong{ public static void main(String args[]){ int num = Integer.parseInt(args[0]); int n = num; //use to check at last time int check=0,remainder; while(num > 0){ remainder = num % 10; check = check + (int)Math.pow(remainder,3); num = num / 10; } if(check == n) System.out.println(n+" is an Armstrong Number"); else System.out.println(n+" is not a Armstrong Number"); } }
class neonn { ; public static void check()throws IOException ; { ; BufferedReader br = new BufferedReader ( new InputStreamReader(System.in)); ; int num; ; System.out.println("Enter the number to be checked!"); ; num=Integer.parseInt(br.readLine()); ; int square; ; square=num*num; //squaring the number ; ; int sum=0; ; ; String sqs=Integer.toString(square); ; for(int i=0; i<sqs.length(); i++) ; sum+=Integer.parseInt(sqs.substring ( i,i+1 ) ) ; ; ; if (sum==num) //checking if the sum of the square is equal to the number entered ; System.out.println(num+" is a Neon Number!"); // if yes. It is neon ; else ; System.out.println(num+" is not a Neon number!"); //otherwise not ; ; } ; }
Dim x As String x = "HELLO" Dim tmpString As String tmpString = Nothing For j = 0 To x.Length - 1 Dim int int=x.Length - 1 int=int-j tmpString=x(j) Next
#include #include void main() { int rev num=0; while(num>0) { rev num=rev num*10+num%10; num=num%10; } return rev_num; } int main(); { int num=4562; printf("reverse of number is%d",reverse digit(num)); getch(); return o; }
Function is_prime(ByVal num As Integer) As Boolean If num < 0 Then num = num * -1 If num < 2 Then Return False If num Mod 2 = 0 Then Return num = 2 Dim max As Integer = Math.Sqrt(num) For div As Integer = 3 To max Step 2 If num Mod div = 0 Then Return False Next Return True End Function Sub Main() For num As Integer = 0 To 100 If is_prime(num) Then Console.Write(num) Console.WriteLine(" is prime") End If Next End Sub
I want to check my num detail
yes you can transfar money in vodafone number is *132*mob num*rupee#
/*Program to find whether given no. is Armstrong or not. Example : Input - 153 Output - 1^3 + 5^3 + 3^3 = 153, so it is Armstrong no. */ class Armstrong{ public static void main(String args[]){ int num = Integer.parseInt(args[0]); int n = num; //use to check at last time int check=0,remainder; while(num > 0){ remainder = num % 10; check = check + (int)Math.pow(remainder,3); num = num / 10; } if(check == n) System.out.println(n+" is an Armstrong Number"); else System.out.println(n+" is not a Armstrong Number"); } }
A three digit number is any number in the range 100 through 999. So you simply check if the number is within this range: #include<iostream> int main (void) { std::cout << "Enter a whole number: "; unsigned num {}; std::cin >> num; // note: check for input errors! if (num>=100 && num<=999) std::cout << num << " has three digits.\n"; else std::cout << num << " does not have three digits.\n"; }
unsigned binary_to_gray (unsigned num) { return num ^ (num >> 1); } unsigned gray_to_binary (unsigned num) { /* note: assumes num is no more than 32-bits in length */ num ^= (num >> 16); num ^= (num >> 8); num ^= (num >> 4); num ^= (num >> 2); num ^= (num >> 1); return num ; }
loop i from 0 to num check if num mod i equals 0breakelsesum = sum + numend the loopprint the sum
num num num
In simple Python code: def convertToAngle(num): while True: if num < 0: num = 360 - num elif num > 360: num -= 360 else: break return num
class neonn { ; public static void check()throws IOException ; { ; BufferedReader br = new BufferedReader ( new InputStreamReader(System.in)); ; int num; ; System.out.println("Enter the number to be checked!"); ; num=Integer.parseInt(br.readLine()); ; int square; ; square=num*num; //squaring the number ; ; int sum=0; ; ; String sqs=Integer.toString(square); ; for(int i=0; i<sqs.length(); i++) ; sum+=Integer.parseInt(sqs.substring ( i,i+1 ) ) ; ; ; if (sum==num) //checking if the sum of the square is equal to the number entered ; System.out.println(num+" is a Neon Number!"); // if yes. It is neon ; else ; System.out.println(num+" is not a Neon number!"); //otherwise not ; ; } ; }
#include<iostream> #include<sstream> #include<exception> std::string decimal_to_roman (unsigned num) { std::stringstream ss {}; while (num>0) { if (num>10000) throw std::range_error ( "ERROR: decimal_to_roman (unsigned num) [num is out of range]"); else if (num==10000) { ss<<"[M]"; num-=10000; } else if (num>=9000) { ss<<"[CM]"; num-=9000; } else if (num>=5000) { ss<<"[D]"; num-=5000; } else if (num>=4000) { ss<<"[CD]"; num-=4000; } else if (num>=1000) { ss<<"M"; num-=1000; } else if (num>=900) { ss<<"CM"; num-=900; } else if (num>=500) { ss<<"D"; num-=500; } else if (num>=400) { ss<<"CD"; num-=400; } else if (num>=100) { ss<<"C"; num-=100; } else if (num>=90) { ss<<"XC"; num-=90; } else if (num>=50) { ss<<"L"; num-=50; } else if (num>=40) { ss<<"XL"; num-=40; } else if (num>=10) { ss<<"X"; num-=10; } else if (num==9) { ss<<"IX"; num-=9; } else if (num>=5) { ss<<"V"; num-=5; } else if (num==4) { ss<<"IV"; num-=4; } else if (num>=1) { ss<<"I"; num-=1; } } return ss.str(); } int main (void) { for (unsigned n=1; n<=10000; ++n) { try { std::cout << n << "\t = " << decimal_to_roman(n) << std::endl; } catch (std::range_error& e) { std::cerr<<e.what()<<std::endl; break; } } }
num 1 is predator num 2 is the beast num 3 is mimi num 4 is peachy and num 5 is centi
Dim x As String x = "HELLO" Dim tmpString As String tmpString = Nothing For j = 0 To x.Length - 1 Dim int int=x.Length - 1 int=int-j tmpString=x(j) Next