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/*Program to find whether given no. is Armstrong or not. Example : Input - 153 Output - 1^3 + 5^3 + 3^3 = 153, so it is Armstrong no. */ class Armstrong{ public static void main(String args[]){ int num = Integer.parseInt(args[0]); int n = num; //use to check at last time int check=0,remainder; while(num > 0){ remainder = num % 10; check = check + (int)Math.pow(remainder,3); num = num / 10; } if(check == n) System.out.println(n+" is an Armstrong Number"); else System.out.println(n+" is not a Armstrong Number"); } }
What else can I help you with?
Write a java program to check a number is Armstrong number?
import java.io.*; public class Jerry { public static void main(String as[]) throws IOException { int k=Integer.parseInt(as[0]); int n=k; int d=0,s=0; while(n>0) { d=n%10; s=s+(d*d*d); n=n/10; } if(k==s) System.out.println("Armstrong number"); else System.out.println("not Armstrong number"); } }
Can you get a Java program to find the cube of a number?
Yes
How to write A Java program to print number of digits in a given number?
One way to do this is to convert the number to a String, then use the corresponding String method to find out the length of the String.
How do you know if you have java?
The best way to find out if your Java is up to date is to visit the Java website. You can then check the latest verison number, and compare it to what is already on your computer. You check in your programs and files. You can also choose to update, and if you have the current version it won't do it.
Change int to string in java?
String.valueOf(number);
Write a java program to check a number is Armstrong number?
import java.io.*; public class Jerry { public static void main(String as[]) throws IOException { int k=Integer.parseInt(as[0]); int n=k; int d=0,s=0; while(n>0) { d=n%10; s=s+(d*d*d); n=n/10; } if(k==s) System.out.println("Armstrong number"); else System.out.println("not Armstrong number"); } }
To find strong number in java?
sir , what is perfect no?
Can you get a Java program to find the cube of a number?
Yes
How do you find out whether Java is installed on Linux?
Enter "java -version" into a terminal. If Java is installed, it will tell you the version number. If it is not installed, it will say "command not found."
Where can one find a Java development kit?
Java Development Kits are best found on the Java website. There are a number of programmes that can be downloaded. It is also possible to get Java Development Kit downloads from the Oracle website.
List all Armstrong numbers between 1 to 5000?
Armstrong numbers are those numbers which are equal to the sum of the digits of the number each raised to the power of the number of digits in the number itself. There are 14 Armstrong numbers in the range 1-5000, which are: 1, 2, 3, 4, 5, 6, 7, 8, 9, 153, 370, 371, 407, 1634.
How do you find a system number in a JAVA program?
If by system number you mean the version number of the Java language on the client computer, you can useSystem.getProperty("java.version"); .Or, if you want the Java virtual machine version number you can use System.getProperty("java.vm.version"); .Finally, if you want the version number of the operating system, you can use System.getProperty("os.version"); .
Which math function is used to find the square root of a number using java?
Math.sqrt(number) function is used to find the square root of a number.. try it
Flow chart for Armstrong number?
armstrong number
How do you write a java program to find the square root of a number?
You can use the Math.sqrt() method.
Where can one find an array of different java application uses?
There are a number of sites that list the many uses of Java applications. The official Java website is one of these sites. Alternatively, one may also find this information at the web domain DynamicDrive.
How do you write a Java program to see whether a number is Armstrong or not... using Buffered Reader and stuff ....?
import java.io.*; class Armstrong { public static void main()throws IOException { BufferedReader in=new BufferedReader(new InputStreamReader(System.in)); System.out.println("Enter a number"); int a=Integer.parseInt(in.readLine()); int n1=a,rev=0,d=0; while(a!=0) { d=a%10; rev=rev+d*d*d; a=a/10; } if(rev==n1) System.out.println("It is a armstrong number "); else System.out.println("It is not a armstrong number "); } }
