0
import java.io.*;
public class Jerry
{
public static void main(String as[]) throws IOException
{
int k=Integer.parseInt(as[0]);
int n=k;
int d=0,s=0;
while(n>0)
{
d=n%10;
s=s+(d*d*d);
n=n/10;
}
if(k==s)
System.out.println("Armstrong number");
else
System.out.println("not Armstrong number");
}
}
What else can I help you with?
To find Armstrong number in java?
/*Program to find whether given no. is Armstrong or not. Example : Input - 153 Output - 1^3 + 5^3 + 3^3 = 153, so it is Armstrong no. */ class Armstrong{ public static void main(String args[]){ int num = Integer.parseInt(args[0]); int n = num; //use to check at last time int check=0,remainder; while(num > 0){ remainder = num % 10; check = check + (int)Math.pow(remainder,3); num = num / 10; } if(check == n) System.out.println(n+" is an Armstrong Number"); else System.out.println(n+" is not a Armstrong Number"); } }
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To find Armstrong number in java?
/*Program to find whether given no. is Armstrong or not. Example : Input - 153 Output - 1^3 + 5^3 + 3^3 = 153, so it is Armstrong no. */ class Armstrong{ public static void main(String args[]){ int num = Integer.parseInt(args[0]); int n = num; //use to check at last time int check=0,remainder; while(num > 0){ remainder = num % 10; check = check + (int)Math.pow(remainder,3); num = num / 10; } if(check == n) System.out.println(n+" is an Armstrong Number"); else System.out.println(n+" is not a Armstrong Number"); } }
How do you write a C program to check whether the number is odd or even Ps-using DEV complier?
To write a C program to determine if something is odd or even you need to be a programmer. To write a program in C is complicate and only done by programmers.
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Program to check whether the given number is an Armstrong number?
<html> <head> <Script Language="JavaScript"> var a,n,b=0,t; n=parseInt(window.prompt("enter n","0")); t=n; while(n>0) { a=n%10; b=b+a*a*a; n=n/10; } if(b==t) { document.writeln("Armstrong no"); } else { document.writeln("Not an Armstrong no"); } </script> </head> </html>
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