perl -e 'sub f { my $fu = shift; return 1 if $fu == 1; return f($fu - 1) * $fu; } print f(5), "\n";'
just paste that in to a command prompt, change the print f(5) to print f(6) or whatever you want.
Pseudo code+factorial
factorial using recursion style in c++ is unsigned int fact(unsigned int a) { if (a<=1) return 1; else { f*=fact(a-1); return a; } } when using looping structure factorial is unsigned int fact (unsigned int n) { unsigned int i,f=1; for(i=1;i<=n;i++) f*=i ; return f; }
If you really wanted to do this, you could simulate multiplication with repeated addition.
by this program you can find the factorial: #include<iostream> using namespace std; main() { int n,x,f=1; cin>> n; x=0; while(x<n) { x++; f= f*x; } cout<<"factorial is"<<f<<"\n"; system("pause"); return 0; }
/*71.PROGRAM TO FIND FACTORIAL OF A NUMBER USING RECURSION*/ #include<stdio.h> #include<conio.h> int fact(int); void main() { int n,f; clrscr(); printf("Enter number whose factorial is to be calculated: "); scanf("%d",&n); if(n>0) { f=fact(n); printf("factorial of %d is %d",n,f); } else printf("Factorial of numbers less than 1 does not exist"); getch(); } int fact(int n) { int facto=1; if(n>1) facto=n*fact(n-1); else return 1; return(facto); }
To calculate the factorial of a given number in C on a Unix system, you can use a simple recursive or iterative function. Here's an example of an iterative approach: #include <stdio.h> unsigned long long factorial(int n) { unsigned long long result = 1; for (int i = 1; i <= n; i++) { result *= i; } return result; } int main() { int number; printf("Enter a positive integer: "); scanf("%d", &number); printf("Factorial of %d is %llu\n", number, factorial(number)); return 0; } Compile the code using gcc filename.c -o factorial and run it with ./factorial to calculate the factorial of a number.
Unix files do not rely on extensions, therefore there is no command to find them.
chutia mc,bc bhosdika
To find the factorial of each element in an array using pointers in C, you can create a function that takes a pointer to the array and its size as parameters. In the function, iterate through the array using pointer arithmetic, calculating the factorial for each element and storing the result back in the same array or a separate array. For calculating the factorial, you can use a simple loop or recursion. Finally, print or return the modified array with the factorials.
Use the 'uname -a' command. It reports on the Unix system, version, machine name, amongst other things.
Here's a simple Java program to find the factorial of a given number using a recursive method: import java.util.Scanner; public class Factorial { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.print("Enter a number: "); int number = scanner.nextInt(); System.out.println("Factorial of " + number + " is " + factorial(number)); } static int factorial(int n) { return (n == 0) ? 1 : n * factorial(n - 1); } } This program prompts the user for a number and calculates its factorial recursively.
Pseudo code+factorial
OS-dependent.stat for unix, FindFirstFile for Windows.
factorial using recursion style in c++ is unsigned int fact(unsigned int a) { if (a<=1) return 1; else { f*=fact(a-1); return a; } } when using looping structure factorial is unsigned int fact (unsigned int n) { unsigned int i,f=1; for(i=1;i<=n;i++) f*=i ; return f; }
#include #include using std::cin;using std::cout;using std::endl;using std::tolower;long factorial(const int& N);int main(){int N = 0; //factorial of Nchar command = 'n';do{cout > N;cout
If you really wanted to do this, you could simulate multiplication with repeated addition.
To calculate the factorial of a number in a shell script, you can use a simple loop. Here's a basic example: #!/bin/bash factorial=1 read -p "Enter a number: " num for (( i=1; i<=num; i++ )) do factorial=$((factorial * i)) done echo "Factorial of $num is $factorial" This script prompts the user for a number, computes its factorial using a for loop, and then prints the result.