If you really wanted to do this, you could simulate multiplication with repeated addition.
#include <iostream> using namespace std; int main() { int i, number=0, factorial=1; // User input must be an integer number between 1 and 10 while(number<1 number>10) { cout << "Enter integer number (1-10) = "; cin >> number; } // Calculate the factorial with a FOR loop for(i=1; i<=number; i++) { factorial = factorial*i; } // Output result cout << "Factorial = " << factorial << endl;
double factorial(double N){double total = 1;while (N > 1){total *= N;N--;}return total; // We are returning the value in variable title total//return factorial;}int main(){double myNumber = 0;cout > myNumber;cout
Pseudo code+factorial
import java.math.BigInteger; public class Factorial { public static void main(String[] args) { BigInteger n = BigInteger.ONE; for (int i=1; i<=20; i++) { n = n.multiply(BigInteger.valueOf(i)); System.out.println(i + "! = " + n); }
That's not the factorial of any number. For a start, the factorial of any number greater than or equal to 2 is even, because of the factor 2. The factorial of any number greater or equal to five ends with 0. Another answer: I suspect the questioner meant to ask how to write 8*7*6*5*4*3*2*1 as a factorial. If so, then the answer is "8!"
Factorial is calculated by taking the number and multiplying it continually by 1 less than that until you finally multiple by 1. For example 6! = 6x5x4x3x2x1 = 720
Take the total number of letters factorial, then divide by the multiple letters factorial (a and e). 7! / (2!*2!) or 1260.
To calculate the number of zeros in a factorial number, we need to determine the number of factors of 5 in the factorial. In this case, we are looking at 10 to the power of 10 factorial. The number of factors of 5 in 10! is 2 (from 5 and 10). Therefore, the number of zeros in 10 to the power of 10 factorial would be 2.
#include <iostream> using namespace std; int main() { int i, number=0, factorial=1; // User input must be an integer number between 1 and 10 while(number<1 number>10) { cout << "Enter integer number (1-10) = "; cin >> number; } // Calculate the factorial with a FOR loop for(i=1; i<=number; i++) { factorial = factorial*i; } // Output result cout << "Factorial = " << factorial << endl;
The time complexity for calculating the factorial of a number is O(n), where n is the number for which the factorial is being calculated.
double factorial(double N){double total = 1;while (N > 1){total *= N;N--;}return total; // We are returning the value in variable title total//return factorial;}int main(){double myNumber = 0;cout > myNumber;cout
Pseudo code+factorial
In Prolog, a simple factorial program can be defined using recursion. Here's a basic implementation: factorial(0, 1). % Base case: factorial of 0 is 1 factorial(N, Result) :- N > 0, N1 is N - 1, factorial(N1, Result1), Result is N * Result1. % Recursive case You can query the factorial of a number by calling factorial(N, Result). where N is the number you want to compute the factorial for.
import java.math.BigInteger; public class Factorial { public static void main(String[] args) { BigInteger n = BigInteger.ONE; for (int i=1; i<=20; i++) { n = n.multiply(BigInteger.valueOf(i)); System.out.println(i + "! = " + n); }
A big number.
The factorial of a number is the product of all the whole numbers, except zero, that are less than or equal to that number.
Yes, a multiple is "a number that can be divided by another number without a remainder".