Basically if you know the Voltage supply and the power used by an appliance then you use the formula for power which is Power = Volts x Amps.
Rearrange so Amps (current) = Power / Volts
If power was 2400 Watts and Volts was 240 the Current would be 2400 / 240 = 10 Amps
wattage is voltage and amperage multiplied. example V/A=W or 120v x 20a=2400 watts
If you add one extra bulb and the voltage remains constant, then you have doubled the current drained from the regulator. 12 Volt and One 12 Watt lightbulb drains 1 Ampere Current. 12 Volt and Two 12 Watt light bulbs drains 2 Ampere Current. However: If having a 24 volt powersource and you add two 12 Volt 12 Watt in serial, then you still only drain 1 Ampere Current. NOTE: Wattage and Voltage of bulbs may be different even if the sockets are the same. Lower voltage on the bulb will increase the current drain, if voltage is a lot lower it might cause the circuit delivering voltage to burn out or blow a fuse. It can also quickly burn the bulb, sometimes in a fraction of a second. It will however do little damage to add a bulb with higher voltage than the circuit is designed for. You will then only observe that you do not get the light you might hope for. Total Current/Ampere= Combined Wattage divided by Voltage Total Wattage = Combined Current or Ampere multiplied by Voltage. Regards.
If you add one extra bulb and the voltage remains constant, then you have doubled the current drained from the regulator. 12 Volt and One 12 Watt light bulb drains 1 Ampere Current. 12 Volt and Two 12 Watt light bulbs drains 2 Ampere Current. However: If having a 24 volt power source and you add two 12 Volt 12 Watt in serial, then you still only drain 1 Ampere Current. NOTE: Wattage and Voltage of bulbs may be different even if the sockets are the same. Lower voltage on the bulb will increase the current drain, if voltage is a lot lower it might cause the circuit delivering voltage to burn out or blow a fuse. It can also quickly burn the bulb, sometimes in a fraction of a second. It will however do little damage to add a bulb with higher voltage than the circuit is designed for. You will then only observe that you do not get the light you might hope for. Total Current/Ampere= Combined Wattage divided by Voltage Total Wattage = Combined Current or Ampere multiplied by Voltage. In simpler words: If you double the bulbs, twice the current is drained from the battery
All you can do is get in the ballpark knowing resistance of windings and the supply voltage. Current = Voltage divided by resistance. Wattage = voltage x current x power factor. For a motor the power factor is between zero and sone number less than one, with one being just a resistive load. So if you calculate the current and use a PF = 1 you can get worse case wattage.
The current will drop. Y??See it this way - resistance is something that opposes current flow. Voltage is the one that helps the current to get across the resistance. So if u have a high resistance, u need a high voltage to get the same current across.But all the values are solely dependent on the output required.Hope that helps.
To calculate wattage, you need to multiply the voltage (V) by the current (I). The formula is: Wattage (W) = Voltage (V) x Current (I). This formula applies to electrical circuits where the voltage is known and the current is flowing.
Current depends on the Wattage and the voltage rating of the device.
Current.
You'd need to know either the resistance or the wattage of the circuit. Ohm's Law: Current = Voltage divided by resistance or Current = Power divided by Voltage
No, the electrical meter reads watts by multiplying the voltage and the amperage used in electrical circuits. Using oversize wire does not govern the amperage flow to the load. The load resistance in the circuit is what governs the amount of current that flows through the wire. This current in the load circuit is multiplied by the voltage applied to the circuit at the electrical meter. The product of this multiplication is wattage, multiplied by the amount of time the load is on, is what the electrical utility bill is based on.
A watt is a measure of electrical power. If you want to know how much current a circuit will draw, and you have wattage ratings of appliances or devices then you can calculate the current. {Power = Voltage × Current}. On a 110 Volt circuit, you can add up the wattages and then divide by 110 volts, to get current in amperes.
It depends by how much it changes. Power (watts) = current (amps) x voltage If the current halves and the voltage doubles, the power won't change. But if the current is cut in half and the voltage only goes up by a little bit the watts will go down. If the current only goes down a little bit but the voltage doubles, then the watts will go up.
To find the actual wattage of an electrical component, you can calculate it by multiplying the voltage across the component by the current flowing through it, using the formula Watts = Volts * Amps. Alternatively, you can refer to the product specifications provided by the manufacturer, which usually list the wattage of the component.
Current or amperage, is wattage divided by voltage. 60 / 120 = .5 amp.
Current or amperage, is wattage divided by voltage. 60 / 120 = .5 amp.
Current or amperage, is wattage divided by voltage. 60 / 120 = .5 amp.
Common sense with electrical systems dictates that current in a circuit be limited to 80% of nameplate (20A). The number of 150W lamps will be limited to 12 in this scenario. This answer can be superseded by local ordinance.