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What else can I help you with?
Write an iterative function to search an element in a binary search tree?
_node* search (_node* head, _key key) { _node* node; for (node=head; node != NULL;;) { if (key == node->key) return node; else if (key < node.>key) node = node->left; else node = node->right; } return node; }
Algoritm for deleting the last element from a list?
Given a list and a node to delete, use the following algorithm: // Are we deleting the head node? if (node == list.head) { // Yes -- assign its next node as the new head list.head = node.next } else // The node is not the head node { // Point to the head node prev = list.head // Traverse the list to locate the node that comes immediately before the one we want to delete while (prev.next != node) { prev = prev.next; } end while // Assign the node's next node to the previous node's next node prev.next = node.next; } end if // Before deleting the node, reset its next node node.next = null; // Now delete the node. delete node;
Is null node equal to leaf node?
No. A leaf node is a node that has no child nodes. A null node is a node pointer that points to the null address (address zero). Since a leaf node has no children, its child nodes are null nodes.
How many pointers will have to be changed if a node is deleted from a linear linked list?
For a singly-linked list, only one pointer must be changed. If the node about to be deleted (let's call it node for the sake of argument) is the head of the list, then the head node pointer must be changed to node->next. Otherwise, the node that comes before the deleted node must change its next pointer to node->next. Note that given a singly-linked node has no knowledge of its previous node, we must traverse the list from the head in order to locate that particular node, unless the node is the head of the list: void remove (List* list, Node* node) { if (!list !node) return; // sanity check!if (list->head == node) {list->head = node->next;} else {Node* prev = list->head;while (prev->next != node) prev = prev->next; // locate the node's previous nodeprev->next = node->next;}} Note that the remove function only removes the node from the list, it does not delete it. This allows us to restore the node to its original position, because the node itself was never modified (and thus still refers to its next node in the list). So long as we restore all removed nodes in the reverse order they were removed, we can easily restore the list. In order to delete a node completely, we simply remove it and then free it:void delete (List* list, Node* node) {if (!list !node) return; // sanity check!remove (list, node);free (node);} For a doubly-linked list, either two or four pointers must be changed. If the node about to be deleted is the head node, then the head node pointer must be changed to n->next and n->next->prev must be changed to NULL, otherwise, n->prev->next becomes n->next. In addition, if the node about to be deleted is the tail node, then the tail node pointer must be changed to n->prev and n->prev->next must be changed to NULL, otherwise, n->next->prev becomes n->prev. Deletion from a doubly-linked list is generally quicker than deletion from a singly linked list because a node in a doubly-linked list knows both its previous node and its next node, so there's no need to traverse the list to locate the previous node to the one being deleted. void remove (List* list, Node* node) {if (!list !node) return; // sanity check!if (list->head == node) {list->head = node->next;node->next->prev = NULL;} else {node->prev->next = node->next; }if (list->tail == node) {list->tail = node->prev;node->prev->next = NULL;} else {node->next->prev = node->prev; }} Again, to physically delete the node we simply remove and then free the node:void delete (List* list, Node* node) {if (!list !node) return; // sanity check!remove (list, node); free (node); }
How do you recursively reverse a singly linked list using c plus plus?
In this case recursion is not necessary, an iterative process is more efficient. Start by pointing at the head node. While this node has a next node, detach its next node and insert that node at the head. Repeat until the original head node has no next node. At that point the head has become the tail and all the nodes are completely reversed. The following example shows how this can be implemented, where the list object contains a head node (which may be NULL), and each node has a next node. The tail node's next node is always NULL. void reverse(list& lst) { if( node* p=lst.head ) { while(p->next) { node* n=p.next; // point to the next node p.next=n.next; // detach the next node n.next=lst.head; // insert the detached node at the head lst.head=n; // set the new head node } } }
Which is faster fpga or cpld?
FPGA is sutiable for complicated arch than CPLD. CPLD is very tiny when compared to the logic of FPGA so CPLD is faster.
How is it determined whether a lymph node has cancer cells?
The only method to identify whether or not a lymph node has cancer cells, is to surgically remove the node and perform examination with a microscope to detect abnormal cancer cells.
Full form of cpld?
Complex programmable logic device
Altera flex logic-10000 series cpld?
yes
Leading manufacturers for cpld and fpga?
Xilinx, Altera, Lattice
What are two functions of mac addresses in a lan?
To uniquely identify a node on a network and to allow the transfer of frames from source to destination
What is lymphiscintigraphy?
Lymphoscintigraphy (sentinel lymph node mapping) is an imaging technique used to identify the lymph drainage basin, determine the number of sentinel nodes, differentiate sentinel nodes from subsequent nodes, locate the sentinel node in an unexpected location, and mark the sentinel node over the skin for biopsy.
What is synthesis in VHDL?
A VHDL program is written to realize an electronic circuit, system or design. After simulating the code, one needs to dump it into an FPGA or CPLD. This programmable logic device, after dumping, act like the designed system. The inter connections of these devices need to be made as per the code. This means that that a program code which might be logic based now needs to be converted into a physically realizable structure. This involves building a physical structure within an FPGA or CPLD. This process involves converting the VHDL code into a format that can be understood by FPGA or CPLD. Converting our code into 1s and 0s that suit the FPGA or CPLD structure is called synthesis.
Write an iterative function to search an element in a binary search tree?
_node* search (_node* head, _key key) { _node* node; for (node=head; node != NULL;;) { if (key == node->key) return node; else if (key < node.>key) node = node->left; else node = node->right; } return node; }
How to Print data of all nodes of linked list?
for (node=head; node!=null; node=node->next) printnode(node);
How to find the mirror image of a binary tree?
Refer to http://cslibrary.stanford.edu/110/BinaryTrees.html void mirror(struct node* node) { if (node==NULL) { return; } else { struct node* temp; // do the subtrees mirror(node->left); mirror(node->right); // swap the pointers in this node temp = node->left; node->left = node->right; node->right = temp; } }
Can we use doubly linked list as a circular linked list?
Yes. The tail node's next node is the head node, while the head node's previous node is the tail node.
