Assuming the gene/allele for a tall plant is dominant and short is recessive this is an impossibility. As in order for both parent plants to be short both chromosomes must contain the t (allele for short) and so the T (allele for tall) cannot be present and will not be passed on to the offspring and it cannot be tall.
TT system is normally used for consumer power supply.No earthing system provided by power distributor.The owner must install the earthing protection by their own connection to the earth.They must installing a suitable electrode and safe arrangement for which they are responsibility to their installation.
The time.h include file is a header file for a library of standard time and date manipulation routines. For example... #include <stdio.h> #include <time.h> int main (int argc, char ** argv) { time_t tt = time(NULL); printf ("The date and time is %s", asctime(localtime(&tt))); return 0; }
// Indexed Allocation #include #include #include struct node { int file_name; int data; int is_free; int size; int directory; int cnt; struct node* link; struct node* inner_link[30]; }; struct node* defaultFile() { struct node* temp = (struct node*)malloc( sizeof(struct node) ); temp->link = NULL; temp->is_free=0; temp->data='a'; temp->file_name=99; temp->directory = 1; return temp; } struct node* insert(struct node *rt, int size, int fname) { struct node* temp = rt; struct node* first=NULL,*last=NULL,*tt=NULL; int flag=0,act_size=0, inner_fname=100,cnt=0; last=first; act_size = size; if ( size>temp->size ) { printf("There is not enough space on the disk to write that file\n"); return rt; } while( temp->link ) { temp = temp->link; } first = defaultFile(); while( act_size>0 ) { tt = defaultFile(); if (act_size>50) tt->size = 50; else tt->size = act_size; tt->file_name = inner_fname; first->inner_link[cnt] = tt; tt->directory = 0; tt->is_free = 0; act_size -= 50; inner_fname += 1; cnt += 1; } temp->link = first; first->is_free = 1; first->cnt = cnt; first->size = size; first->file_name = fname; act_size = rt->size; rt->size = act_size-size; return rt; } void printFiles(struct node* rt) { struct node *temp = rt, *tt; int first=0,cnt=0; printf("format is (File name, size)\n"); printf("\t(%d,%d)\n",rt->file_name,rt->size); while( temp ) { if ( temp->is_free ) { printf("\t(%d,%d)\n",temp->file_name,temp->size); first = 0; while( cntcnt ) { tt = temp->inner_link[cnt]; printf("\t\t(%d,%d)\n",tt->file_name, tt->size); cnt += 1; } printf("\n"); } temp = temp->link; } } struct node* combine(struct node *rt,int fname) { struct node *temp=rt,*nt=NULL,*temp1=temp->link; int size=0; if ( rt->file_name==fname ){ printf("You cannot that file as thats just to show that that much amount of space is left in the disk\n"); return rt; } while( temp1 ) { if (temp1->is_free==0 && temp1->file_name==fname ) { size = temp1->size; temp->link = temp1->link; temp1 = temp->link; } else { temp = temp1; temp1 = temp1->link; } } rt->size += size; return rt; } struct node* deleteFiles(struct node* rt, int fname) { struct node *temp = rt,*nt=NULL; int flag=0; while( temp && flag==0 ) { if (temp->file_name==fname) { temp->is_free=0; flag=1; } temp = temp->link; } if( flag==0 ){ printf("There doesnt exist any file with that name\n"); } return combine(rt,fname); } int main() { int flag,no,size,data; struct node *root; root = defaultFile(); root->size=1000; data=100; flag=no=size=0; while( flag==0 ) { printf("Enter no's \n1.insert\n 2.Delete\n 3.Print files \n 4.Exit\n"); scanf("%d",&no); printf(" no is %d\n",no); switch(no) { case 1: printf("Enter file size\n"); scanf("%d",&size); root = insert(root, size, data); data = data+1; break; case 2: printf("Enter file name to delete\n"); scanf("%d",&size); root = deleteFiles(root, size); break; case 3: printFiles(root); break; case 4: flag=1; printf("Quitting from loop\n"); break; default: printf("Enter a valud no \n"); break; } } }
If you are on AQA, you can check for your subject and whether AS or A2 on this subject http://store.aqa.org.uk/admin/t_table_pdf/AQA-TT-GCE-JUN09.PDF
A gold TT bar is a Ten Tola bar. A tola was a vedic measure that was equal to 100 ratti seeds. Currently a TT bar is equivalent to 116.64 grams.
Five types of earthing systems are there..They are as TT system, IT system, TN-S system, TN-C-S system, TN-C system
Tt, tt -- novanet :)
The possible offspring outcomes of this cross would be 50% Tt (heterozygous) and 50% tt (homozygous recessive).
Five types of earthing systems are there..They are as TT system, IT system, TN-S system, TN-C-S system, TN-C system
rather TT Tt tt
TT Tt tt
Tt X Tt Statistically, 1 TT Homozygous dominant, expresses T. 2 Tt Heterozygous dominant, expresses T. 1 tt Homozygous recessive, expresses t.
Tt, tt -- novanet :)
The offspring will have a 25% chance of being TT (homozygous dominant), a 50% chance of being Tt (heterozygous), and a 25% chance of being tt (homozygous recessive). This follows Mendel's law of segregation where alleles for a trait separate during gamete formation.
These are letters assigned to alleles or variations in genes. TT means that there are two dominate alleles. Tt means that there is one dominate and one recessive and tt means that both are recessive.
Nope! TT is the dominant phenotype (what ever it may be) and tt is the recessive phenotype (what ever that may be).So say T is the allele for Tall plants, t is the allele for short plants. TT would be show the tall phenotype while tt would show the short phenotype. If the genotype was Tt, the phenotype would be tall as well because the T is dominant and masks the phenotype of t (short plants).