How do you reverse an array in c?

Answer 1

#include <iostream>

using namespace std;

int main()

{

const int max=26;

char c[max];

int i, j;

// Initialise array with letters of the alphabet (ascending order).

for(i=0; i<max; ++i )

c[i]='a'+i;

// Print array.

for(i=0; i<max; ++i)

cout<<c[i];

cout<<endl;

// Reverse array:

// work from both ends, swapping elements as we go,

// stopping when we reach the middle elements.

for(i=0, j=max-1; i<j; ++i, --j)

// Swap values without using a temporary variable.

c[i]^=c[j]^=c[i]^=c[j];

// Print array.

for(i=0; i<max; ++i)

cout<<c[i];

cout<<endl;

return(0);

}

Output:

abcdefghijklmnopqrstuvwxyz

zyxwvutsrqponmlkjihgfedcba

Answer 2

#include

using std::cin;
using std::cout;
using std::endl;

int main()
{
const int arraySize = 128;
char myString[arraySize] = {'0'};
cout << endl << "Enter a string: " << endl;
cin.getline(myString, 128, '\n');

int numberOfChars = 0;
while ((numberOfChars < (arraySize - 1)) && (myString[numberOfChars] != NULL))
{
++numberOfChars;
}
cout << endl << "You've entered:"
<< endl << myString << endl;

char myStringReversed[arraySize] = {'0'};
int index = 0;
while ((index <= numberOfChars) && (myString[index] != NULL))
{
myStringReversed[numberOfChars - index - 1] = myString[index];
++index;

}
cout << endl << "Reversed string is: "
<< endl << myStringReversed << endl;

system("PAUSE");
return 0;

}

Answer 3

Working from each end of the array to the middle element(s), swap the corresponding elements.

Answer 4

for (i=maxindex; i>=0; i--) printf("index: %d value: %d\n", i, array[i]);

Answer 5

Point to both ends of the array and swap the elements. Work your way towards the middle, swapping as you go. When the pointers meet or cross each other, you are done.

Answer 6

Point to both ends of the array. Work towards the middle swapping values as you go. When the pointers meet or cross each other, the array is completely reversed.