In Java, you would create an array of type BigInteger, then initialize each object (each array element) with the newoperator. I believe it would be something like this: BigInteger[] myArray = new BigInteger[5]; for (int i = 0; i
I don't think this can be done. Why do you want to do it without operators, anyway? It is fairly simple to use them. - Of course, you could write a method that adds two numbers, but your method will internally still have to use operators. ----------------------------------------- Reply by lordstriker24@yahoo.com import java.math.BigInteger; public class MultiplyTest { public static void main(String[] args) { BigInteger bigInt1 = new BigInteger("5"); BigInteger bigInt2 = new BigInteger("8"); System.out.println(bigInt1.add(bigInt2)); } }
There are many ways of solving this problem using primitive types. However, if you are willing to sacrifice some memory, you can use BigInteger's gcd() method to make things easy. Example: public static int gcd (int[] numbers) { BigInteger k = BigInteger.ZERO; for (int n : numbers) k = k.gcd(new BigInteger(""+n)); return k.intValue(); }
It's actually not true. In order to make a good program which can work with big arrays you have to use dynamic arrays because you can cleam memory used by dymanic arrays any time. For static arrays is not true, memery which was reserved for static arrays will be available for other applications only when you finish working with your application (which is working with static arrays).
You don't need to use ampersand for arrays; it's entirely optional even for strings (character arrays). This is because arrays will implicitly convert to a pointer at the slightest provocation. Thus for an array named X, you can either pass the array to a function as X, &X or &X[0], they all refer to the exact same address.
Sir, your question is not clear. If you just want to multiply 3 and 24 then why are you trying to use arrays for such simple calculation.
Java has a built-in arbitrary-precision integer class called BigInteger. BigInteger can take a number in String format and represent it as a number. // First huge number (larger than can be held in a Long). BigInteger bigIntA = new BigInteger("123456789012345678901234567890"); // Second huge number BigInteger bigIntB = new BigInteger("987654321098765432109876543210"); // bigIntAB = bigIntA * bigIntB BigInteger bigIntAB = bigIntA.multiple(bigIntB);
import java.math.*; class AddNumbers { public static void main(String[] args) { BigInteger num1=new BigInteger("100"); BigInteger num2=new BigInteger("50"); BigInteger result=num1.add(num2); System.out.println(result); } }
name two smaller arrays you can use to find the product
Fortunately for us, Java can handle arbitrarily-large numbers via the BigInteger class. This will compute and print out the value of 2999 final BigInteger TWO = BigInteger.valueOf(2L); final int exponent = 999; final BigInteger answer = TWO.pow(exponent); System.out.println(answer);
To improve the signal :)
using BigInteger in Java the solution came out to 57059537794043649407224429209731939614293432863825926865326985015341245046424688863610945101859121700977706958317102987733458968947434606
I don't think this can be done. Why do you want to do it without operators, anyway? It is fairly simple to use them. - Of course, you could write a method that adds two numbers, but your method will internally still have to use operators. ----------------------------------------- Reply by lordstriker24@yahoo.com import java.math.BigInteger; public class MultiplyTest { public static void main(String[] args) { BigInteger bigInt1 = new BigInteger("5"); BigInteger bigInt2 = new BigInteger("8"); System.out.println(bigInt1.add(bigInt2)); } }
There are many ways of solving this problem using primitive types. However, if you are willing to sacrifice some memory, you can use BigInteger's gcd() method to make things easy. Example: public static int gcd (int[] numbers) { BigInteger k = BigInteger.ZERO; for (int n : numbers) k = k.gcd(new BigInteger(""+n)); return k.intValue(); }
Yes
1363
BAC (Bacterial Artificial Chromosome) arrays are a type of DNA arrays. BAC arrays are usually used for a technique called array CGH (Comparative Genomic Hybridisation) which is used to identify gross deletions or amplifications in DNA (which for example is common in cancer). DNA arrays include BAC arrays but also oligo, cDNA, and promoter arrays. Oligo and cDNA arrays are typically used for gene expression analysis (looking to see how heavily expressed each gene is). Oligo arrays can also be used for SNP (single nucleotide polymorphism) analysis. Promoter arrays are used to identify transcription factor binding sites.
It's actually not true. In order to make a good program which can work with big arrays you have to use dynamic arrays because you can cleam memory used by dymanic arrays any time. For static arrays is not true, memery which was reserved for static arrays will be available for other applications only when you finish working with your application (which is working with static arrays).