How do you write a program in C in alphabetical order?

Answer 1

#include<iostream>

#include<list>

struct item

{

item(const char ch):chr(ch), count(1){}

char chr;

size_t count;

};

int main()

{

const size_t size=50;

size_t idx;

std::list<item> freq;

std::list<item>::iterator iter;

std::string test;

for(idx=0; idx<size; ++idx)

test.push_back('a'+rand()%26);

for(idx=0; idx<size; ++idx)

{

for(iter=freq.begin(); iter!=freq.end() && (*iter).chr!=test[idx]; ++iter);

if( iter!=freq.end() )

++(*iter).count;

else

freq.push_back(item(test[idx]));

}

std::cout<<"Frequency table of the string:\n""<<test.c_str()<<""\n"<<std::endl;

for(iter=freq.begin(); iter!=freq.end(); ++iter)

{

item& itm=*iter;

std::cout<<itm.chr<<" = "<<itm.count<<std::endl;

}

std::cout<<std::endl;

}

Answer 2

You don't. Programs are written as a series of commands that must be executed in a predefined order, branching off wherever decisions dictate. Writing a program in alphabetical order would make no sense.