Yes. As long as the load stays the same. Voltage equals the resistance of the load times the current or amperage. Or , in this case, as an example, if the load is the same, the voltage is 240 and current is 10 amps. At 120 volts, the current is 20 amps. Current x resistance(or the load)=voltage. With simple math, the equation can be moved around.
A: That will happen anytime the voltage source is not able to provide the power needed for the load. If the load exceed the power available from the source the voltage will be reduced as IR drop from the source
If voltage increases when current remains constant then resistance must also increase. Ohm's Law: Voltage = Current times Resistance.
increases
If the voltage applied across the resistor remains constant, then as the resistance of the resistor decreases, the current through it will increase. Consider Ohm's Law: E = IR In this formula, in order for 'E' to remain constant as 'R' decreases, 'I' must increase. Another form of Ohm's Law: I = E/R If 'E' remains constant, then the value of the fraction increases as its denominator 'R' decreases.
If you have a simple circuit. For eg: One voltage source and one resistor, then the voltage of the circuit will always remain the same, the current however will decrease following Ohms' Law V=I*R. If we have a current source instead of a voltage source, we are forcing the current to be a certain value so if we increase the resistor value the current will remain the same but the voltage will increase.
Nothing, but the current will increase.
If the resistance increases, while the voltage stays the same, current will decrease. Current = voltage divided by resistance
it dies
If resistance is increased, current decreases. Ohm's Law: current equals voltage divided by resistance.
A: That will happen anytime the voltage source is not able to provide the power needed for the load. If the load exceed the power available from the source the voltage will be reduced as IR drop from the source
If voltage increases when current remains constant then resistance must also increase. Ohm's Law: Voltage = Current times Resistance.
According to ohms law, V = IR, where V=voltage I= current R = resistance the above formula can also be written as I = V/R, here, resistance is inversely proportional to current. In other words, as resistance increases, current decreases.
increases
If the voltage applied across the resistor remains constant, then as the resistance of the resistor decreases, the current through it will increase. Consider Ohm's Law: E = IR In this formula, in order for 'E' to remain constant as 'R' decreases, 'I' must increase. Another form of Ohm's Law: I = E/R If 'E' remains constant, then the value of the fraction increases as its denominator 'R' decreases.
The current decreases due to I=V/R. The ammeter reading will decrease as R is increased.
If current sensitivity of a galvanometer is increased, the voltage sensitivity remains the same. Voltage sensitivity depends on the resistance of the galvanometer coil, while current sensitivity depends on the number of turns in the coil. Therefore, changing current sensitivity does not affect voltage sensitivity.
The current will also increase. This can be proved by using ohms law, V=IR --> I=V/R, as the resistance is constant the R can be replaced by the number 1 therefore I=V/1 or I=V, hence if the voltage increases the current must also increase.