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To answer this question voltage, power factor, efficiency, and run configuration must be known, none of which was given in the question. I will make some assumptions, to shown how the calculation is done.

Given: 50 HP, three phase. Assumed: 480 volts delta, 0.92 PF, 0.95 EF, and WYE-DELTA start-run configuration.

1 HP (electric motor) is 746 watts, so 50 HP is 37.3 KW. Divide by PF 0.92 and by 0.95 EF to get 42.7 KVA. Divide by 480 V and by 3 to get 29.6 A per winding. Multiply by 1.732 (square root of 3) to get 51.3 A per phase.

Now, 51.3A is a lot of current, requiring large windings and, therefore, a large motor. I would consider a higher voltage motor, such as 4160. Rerun the calculations and you get 5.9A per phase. Does this justify a 4160 service? Its marginal, but you begin to see the issues involved in choosing a motor.

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