One pound of steam contains approximately 1,200 BTUs (British Thermal Units) of energy. This value can vary slightly depending on the pressure and temperature of the steam, but it is a standard approximation used in calculations involving steam systems. For more precise applications, it's important to consider the specific enthalpy of the steam at the given conditions.
There are 1078.9 BTUs.
1MW = 1000 KW 1KW = 860 Kcal/Hour 1 Kcal = 3.968 BTu.
#2 fuel oil = 140,000 btu/gallon. Psi does not matter.
Heptane has the chemical formula of C7H16. It has a BTU rating of 19,163 BTU per pound and a rating of 4,465.8 kilojoules per mole.
Oil has the higher BTU rating Depends. If it is Liquified Nat. Gas then it has the higher rating.
You need to look at a steam table first then Multiply lbs/hr steam x latent heat of evaporation in BTU/lb @ the operating pressure.
There are 1078.9 BTUs.
To calculate the BTUs in a steam line at 140 PSI, you first need to determine the enthalpy of the steam at that pressure. At 140 PSI, the saturation temperature is approximately 366°F, and the enthalpy of saturated steam is about 1,200 BTU per pound. Therefore, if you have the mass flow rate of steam, you can multiply it by the enthalpy to find the total BTUs being carried in the steam line.
114,000 BTU/gallon
1MW = 1000 KW 1KW = 860 Kcal/Hour 1 Kcal = 3.968 BTu.
2500 btu per cubic foot of vapor.
For regular gasoline, 125,000 BTU per US gallon
One BTU per second is 1.434 hp
12,000 btu = 0ne ton
65,000 BTU per hour equates to 19.05 kW
Propylene has a lower heating value of approximately 21,500 BTU per gallon.
1 BTU is required to raise 1lb of water 1 degree F in 1 hour. 212-75=137 degrees 600 lbs water x 137 degrees= 82,200 BTU's required to change 75 degree water to 212 degree water. To change 212 degree water to 212 degree steam it requires 970 btu's (latent heat of vaporization) per lb of water 970 btu x 600 lbs water = 582,000 btu Answer - 582,000 btu+ 82,200 btu = 664,200 btu's