There is no boolean in C, we usually use int/short/char to store logical values.
A java.util.Date object will take about 32 bytes in memory.
in some cases, aloop control variable does not have to be initialized.
Standard answer seems to be 50 million.
please just take this program off of my computer . I need to take care of things and I can not do them if this program is in operation. a thank you
In ASCII code, each letter, number or punctuation mark takes one byte, or 8 bits. That gives you 256 discrete combinations. Two letters take 2 bytes, or 16 bits.
1,000 bytes make a kilobyte
Depending on the movie length, a 1 hour movie will take up to 100,000 bytes to be produced and a 2 hour movie will take around 300,000 bytes.
true or false
2
A java.util.Date object will take about 32 bytes in memory.
16KB, or 16384 bytes, can be addressed with 14 address lines. (214 = 16384)
Approx. 9.3 Gigabytes!
As one byte can hold one letter of the alphabet, to store the word "Sarah" would take 5 bytes.
A plain integer variable in C under windows is 2 bytes in 16 bit windows, and 4 bytes in 32 bit windows.
The answer is 246 sectors. 123 x 1024 bytes per KB = 125,952 total bytes in the file. 125,952 bytes / 512 sectors per cluster = 246 sectors
The number of bytes an integer variable can take depends on the programming language and the system architecture. Typically, in languages like C and C++, an int usually takes 4 bytes (32 bits) on a 32-bit or 64-bit architecture, while a short takes 2 bytes and a long can take 4 or 8 bytes depending on the system. In Python, integers can vary in size and can take more than 4 bytes, depending on their value, as they are dynamically allocated. Always check the specific language documentation for precise details.
The phrase "hello world" consists of 11 characters, including a space. In a typical ASCII encoding, each character takes up 1 byte. Therefore, transmitting "hello world" will take 11 bytes. If you include a newline character at the end, it would take 12 bytes.