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How many bytes AND how many bits in 16 address lines and 4 data lines?
Bytes:32768 Bits:262144
How many no of address lines required in 64kB memory?
To calculate the number of address lines required for a 64 kB memory, first convert 64 kB into bytes: 64 kB = 64 × 1024 bytes = 65,536 bytes. The number of address lines needed can be determined using the formula (2^n = \text{total number of addresses}), where (n) is the number of address lines. Since 65,536 is (2^{16}), you need 16 address lines to address a 64 kB memory.
How many memory address does this number of address lines allow the 8086 to access directly?
The 8086/8088 has 20 address lines. It can access 220, or 1MB, or 1,048,576 bytes of memory.
How many memory addresses does this number of address lines allow the 8086 to access directly?
The 8086/8088 has 20 address lines. It can access 220, or 1MB, or 1,048,576 bytes of memory.
How many bites does an IP address have?
In case of IPv4, the address has 4 bytes. In case of IPv6, the address has 16 bytes.
How many address lines in 8088?
The Intel 8088 microprocessor has 20 address lines. This allows it to address up to 1 MB (2^20 bytes) of memory. The address lines are labeled A0 to A19, enabling the microprocessor to access a wide range of memory locations.
How many no of address lines are required for 512 K word memory?
If you are addressing bytes, then 512K words (16 bit words) requires 20 address lines.I gave that answer because the question was categorized 8086/8088. If you are addressing words, then the answer is 19 address lines.
How many address line required for 10 kb data?
To determine the number of address lines required for 10 KB of data, we first convert 10 KB into bytes, which is 10,240 bytes (since 1 KB = 1,024 bytes). The number of addressable locations is equal to the number of bytes, and to find the number of address lines needed, we can use the formula (2^n \geq \text{number of bytes}). Solving (2^n \geq 10,240), we find that (n) must be at least 14, as (2^{14} = 16,384) is the smallest power of 2 that exceeds 10,240. Therefore, 14 address lines are required.
How many bytes in an IPX network address?
10 bytes - 4 for the network, 6 for the MAC address.
How many address lines are needed to access 256KB of main memory?
The number of address lines needed to access N-KB is given by log2N Then the number of address lines needed to access 256KB of main memory will be log2256000=18 address lines.
How many address lines in Pic16F877A microcontroller?
The PIC16F877A microcontroller has 13 address lines, which allows it to address 8K words of program memory. This enables it to access a range of memory locations for storing instructions. Additionally, it has 368 bytes of data RAM and 256 bytes of Electrically Erasable Programmable Read-Only Memory (EEPROM) for data storage.
How many bytes in a Mac address?
A Mac address is a 48bit addressing scheme (usually represented in HEX). There are 8 bits in a bytes therefore it is 6 bytes long.
