A 2K X 8 memory requires 11 address lines and 8 data lines
17 address lines and 8 data lines. 2^17=128k
How many bits are there in a data link layer ethernet address?
you require 16 input line and 16 output line and 16 address line. Because 64 K = 26 X 210 = 216 so, 16 address lines Here N = 16, so 16 data lines will be there. .
In the 2k*16 , the 11 address lines are required and the 16 input-output lines are required..
In a 256K x 16 memory system, the memory has 256K (256 * 1024 = 262,144) addressable locations and each location holds 16 bits of data. To calculate the number of address lines needed, we find the base-2 logarithm of 256K, which is 18 (since 2^18 = 262,144). For the data lines, since each location holds 16 bits, 16 data lines are required. Thus, the system requires 18 address lines and 16 data lines.
8
12
Microprocessor has 16 address lines and microcontroller has 20 address lines
two
You can address 214 or 16384 different locations with 14 address lines.
commander blander!