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The 8051 microcontroller has four data lines, which are used for the 8-bit data bus. This allows it to transmit data in 8-bit chunks, supporting operations with 8-bit data types. The architecture enables it to interface with various peripherals and memory components effectively.
Microprocessor has 16 address lines and microcontroller has 20 address lines
A 2K X 8 memory requires 11 address lines and 8 data lines
17 address lines and 8 data lines. 2^17=128k
Bytes:32768 Bits:262144
2e24x16
The address lines A0..A15 are multiplexed with the data lines D0..D15 on the pins AD0..AD15
how many interrupts in 8051
The 8051 microcontroller has an 8-bit data bus width. This means it can transfer 8 bits of data simultaneously, allowing it to handle one byte of data at a time. The architecture is designed for efficient processing of 8-bit data, which is common in many embedded applications.
In a 256K x 16 memory system, the memory has 256K (256 * 1024 = 262,144) addressable locations and each location holds 16 bits of data. To calculate the number of address lines needed, we find the base-2 logarithm of 256K, which is 18 (since 2^18 = 262,144). For the data lines, since each location holds 16 bits, 16 data lines are required. Thus, the system requires 18 address lines and 16 data lines.
for 16 MB memory has 24 address lines
There are 20 address lines and 16 data lines in the 8086 microprocessor. The low order 16 address lines are multiplexed with the data lines. Some of the high order address lines are multiplexed with status lines.