1 litre through 1 degree C is 1000 calories, equal to 4200 Joules of energy. The power in watts measures how quickly that happens, so that 4200 watts would do it in 1 second, but 100 watts would take 42 seconds.
It takes approximately 4.184 Joules of heat to raise the temperature of 1 gram of water 1 degree C. 1 Joule is the energy of 1 Watt for 1 second (or 3,600,000 Joules equals 1 Kilowatt-hour). In more real world numbers: It takes 69.7 watts 1 minute to heat a liter of water 1 degree C; or 146.6 watts in 1 minute to heat a gallon of water 1 degree F. A watt is a watt, weather it comes from resistance, radiant or induction. The only variations will come from the efficientcy of the heat source's design and how it is being used.
To convert watts into amperes you divide the circuit voltage into the watts. Amps = Watts/Volts. <<>> Converting Watts to Amps The conversion of Watts to Amps is governed by the equation Amps = Watts/Volts For example 12 watts/12 volts = 1 amp Converting Amps to Watts The conversion of Amps to Watts is governed by the equation Watts = Amps x Volts For example 1 amp * 110 volts = 110 watts Converting Watts to Volts The conversion of Watts to Volts is governed by the equation Volts = Watts/Amps For example 100 watts/10 amps = 10 volts Converting Volts to Watts The conversion of Volts to Watts is governed by the equation Watts = Amps x Volts For example 1.5 amps * 12 volts = 18 watts Converting Volts to Amps at fixed wattage The conversion of Volts to Amps is governed by the equations Amps = Watts/Volts For example 120 watts/110 volts = 1.09 amps Converting Amps to Volts at fixed wattage The conversion of Amps to Volts is governed by the equation Volts = Watts/Amps For Example, 48 watts / 12 Amps = 4 Volts Explanation Amps are how many electrons flow past a certain point per second. Volts is a measure of how much force that each electron is under. Think of water in a hose. A gallon a minute (think amps) just dribbles out if it is under low pressure (think low voltage). But if you restrict the end of the hose, letting the pressure build up, the water can have more power (like watts), even though it is still only one gallon a minute. In fact the power can grow enormous as the pressure builds, to the point that a water knife can cut a sheet of glass. In the same manner as the voltage is increased a small amount of current can turn into a lot of watts.
Use 100 watts
10 volts divided by 30 ohms is 0.33333 amperes. 10 volts times 0.33333 amperes is 3.3333 watts. Note: Resistance is dependent on temperature. 3 watts is enough power to raise the temperature enough to affect the resistance, changing the results.
One hp is 735.5 watts.
Depends on the size of the room (its thermal capacity) and the efficiency of the heating.
It would take approximately 250,000 watts to raise the temperature of 200 liters of water from 83°C to 84°C in one minute. This calculation is based on the specific heat capacity of water and the formula for calculating energy required to raise the temperature of a substance.
1 gallon of water is 4540 cc and 1 degree F is 0.555 degrees C, so raising 4540 cc of water by 0.555 degree C would take 4540x0.555 calories, or 2520 calories. Multiply by 4.2 to convert to joules which gives 10590 joules. Therefore the energy required is 10590 joules which is the same as 10590 watt-seconds. That could be done by 100 watts in 105.9 seconds, or 1000 watts in 10.59 seconds.
Since watt is a unit of power (how fast energy is transferred), you can do this with almost any amount of power - as little or as much as you want, depending on how fast you want to heat the water. The time it takes will depend on the initial temperature, the amount of water, and the power.
2.4705 watts/hour
A watt is a measure of energy, which may or may not be heat, but heat is considered to be the simplest form of energy and is an easy way to compare amounts of energy. Another measure of energy that is easy to work with is a calorie, which is the amount of energy needed to raise the temperature of 1 gram of water by 1 degree C. In these terms without special conditions, this applies only between 0 and 100 degrees C, because freezing and boiling make the equations much more complicated. A watt is approximately 86 calories, meaning that applied to a gram of water would raise its temperature by 86 degrees centigrade. A kilowatt is 1000 watts meaning that it could raise the temperature of that gram of water by 86000 degrees--at least theoretically, but that image is all but useless. So let's say that a kilowatt represents enough heat to raise the temperature of a liter (1000 g) of water by 86 degrees C.
At high temperature (high power in watts) water is evaporated faster.
To determine the time this will take, you need to know the rate at which heat is being added to the system. The specific heat capacity of a substance is the amount of energy required to raise the temperature of one gram of a substance one degree centigrade. For water at 25oC, the specific heat capacity is 4.184 J*g-1*oC-1. That is, if you have one gram of water, you must add 4.184 Joules of energy (heat) to raise the temperature one one degree centigrade. The time it takes for the temperature increase to happen depends on how quickly you add the 4.184 J. Adding heat at a rate of 1 Joule/second (which is equivalent to 1 Watt), it is easy to see that it will take 4.814 seconds to raise the temperature of the gram of water one degree centigrade. The first step to solving your problem, then, is to make your data units compatible with your known constants. We need to convert volume to mass. We do this by means of density. The density of liquid water at standard temperature and pressure is 1g/mL. 1L H2O *1000mL/1L *1g H2O/mL H2O= 1000g H2O Then, to find the amount of energy required to change the temperature of the mass, we use the specific heat. 1000g H2O *4.184J/(g*K)= 4184 J/oC Note the units on this last value. They give the amount of energy needed required per degree centigrade of change in the temperature. That is, it requires 4814J to change the temperature of 1000g H2O one degree centigrade. Given the time rate of heat transfer into the system, you can find the time required to make the change. If, for instance, your heat exchange rate is 5 Watts (J/s), you would have 4184 J/oC * 1 second/5 Joules = 836.8 s/oC This value allows you to calculate the time required for any change in temperature simply by multiplying the number of degrees centigrade temperature change. For one degree, we find 836.8 s/oC *1oC = 836.8s
The amount of energy required to freeze water depends on the initial temperature of the water and the desired final temperature (0°C for freezing water). To calculate the power in watts needed to freeze water, you would need to know the mass of water, its initial temperature, and the time over which you want to freeze it.
That depends how fast you want to do this. Please note that "watt" is not a unit of energy, it's a unit of power (energy per time unit).
The more watts your oven has, the faster the temperature increases.
It takes about 4.18 Joules of energy to heat 1 gram of water by 1 degree Celsius. Therefore, to heat 1 liter (1000 grams) of water by 1 degree Celsius, it would require about 4180 Joules. Converting this to watts depends on the time taken to heat the water.