The largest 120V motor generally available is 3hp. A 3hp, 120V motor draws about 30 amperes. All true 5hp motors I have seen are 230V or higher.
Note that some motors, such as compressors and vacuum cleaners, use artificially high hp numbers to entice you to buy their unit (they will use terms like peak-developed hp, etc.). These ratings are not true hp, and you just have to go by the nameplate rating on the unit.
For instance, I have a Sanborn Air Compressor that claims 4 PEAK horsepower, yet only draws 17 amperes at 120V. Its really closer to a 2hp motor.
The wiring should allow for 115 amps.
Probably not. The single phase three horse power motor will be much larger in physical size than its three phase counterpart, and will probably not fit.
A 0.75 kW (750 W) single-phase motor operating at 220 V will typically have a full-load running current of about 3.4 A, calculated using the formula ( I = \frac{P}{V} ) (where ( P ) is power in watts and ( V ) is voltage). The starting current, or inrush current, can be significantly higher, often ranging from 4 to 7 times the running current, depending on the motor type and load conditions. Therefore, the starting current could be approximately 13.6 A to 23.8 A.
For 1 hp motor, a single phase starter is used. Because a single phase starter gives economy consumption,easy trouble shooting and easy installation when compared to three phase starters and supply....
22 kw motor how much takes ampares with load
To calculate the current per phase, use the formula: Current (I) = Power (P) / (Square Root(3) x Voltage (V)). For an 18kW motor at 415V, the current per phase will be: 18,000W / (1.732 x 415V) ≈ 24.5A per phase.
A 240V 3-phase motor is generally more efficient compared to a 120V single-phase motor of the same horsepower rating because it provides smoother and more consistent power delivery. The 3-phase motor also tends to have lower operating temperatures and reduced energy losses, resulting in higher efficiency and better performance overall.
Using the formula Power = Voltage x Current, we can calculate the current: Current = Power / Voltage. Plugging in the values, we get 1500W / 120V = 12.5A. So, a 1500W resistance heater would draw 12.5A of current at 120V.
question is incomplete, I think you ask how much current consumed by this motor. for starting this motor we need a star/delta starter and a three phase supply.
P=VI P=power V=voltage I=current therefore current drawn is 5000/400=50/4=12.5 amperes
The wiring should allow for 115 amps.
118.72 amp current will be consumedAnswerFirst of all, 70 horsepower is the machines output, not its input, so you cannot calculate its current without knowing its efficiency. Secondly, the current also depends on the type of motor -is it a.c. or d.c? Is it single-phase or three-phase? Without this information, your question cannot be answered.
Using the formula Power = Voltage x Current, you can rearrange to solve for current: Current = Power / Voltage. Plugging in the values, the hair dryer would draw 10 amps of current (1200W / 120V).
A capacitor is used in a ceiling fan to control the speed of the motor by altering the phase angle between the current and voltage. Capacitors help the motor to start and run smoothly at different speeds without drawing too much current. It also helps in reducing power consumption and improving the efficiency of the fan.
Probably not. The single phase three horse power motor will be much larger in physical size than its three phase counterpart, and will probably not fit.
Free
A 0.75 kW (750 W) single-phase motor operating at 220 V will typically have a full-load running current of about 3.4 A, calculated using the formula ( I = \frac{P}{V} ) (where ( P ) is power in watts and ( V ) is voltage). The starting current, or inrush current, can be significantly higher, often ranging from 4 to 7 times the running current, depending on the motor type and load conditions. Therefore, the starting current could be approximately 13.6 A to 23.8 A.