Yes you can. The UF is a significantly faster diode. The peak forward surge current is 50 amps less, but apart from that they have much the same characteristics.
It depends on the particular zener diode. Typically, they will pull 75 ma of current.
Consider ideal diode to be connected in series with resistor of 6kSilicon diode forward bias voltage = 0.7 voltsCurrent across 6k resistor = (5-0.7)/6000 amperesVoltage across {resistor + diode}=4.3 + 0.7=5vIf silicon internal resistance is 6k then voltage across diode=5vIf external resistance is 6k and diode resistance is negligible then voltage across diode=0.7v
The diode voltage drop is 0.7 volts, so you need that much to turn it on. Current is controlled by a resistor in series.
About 0.2V
The answer is pretty much "No." You can increase the power slightly, but if you go much beyond what it's designed for you'll burn out the laser diode.
This type of smoke detector is more sensitive. It uses a laser diode in the sensor instead of an LED which allows it to be much more sensitive.
The power of a laser beam is typically measured in watts (W). This measurement indicates how much energy the laser beam is emitting per unit of time.
Power consumed by a resistance is I2R
There's more than one type of laser. Diode lasers are pretty much ready to go immediately, but you don't want them to push too much power, as they can then heat up to the point of failure. Other lasers, particularly high powered chemical lasers, rely on a several complicated sub-systems to fire, and will need quite some time to get ready for action.
Yes you can. The UF is a significantly faster diode. The peak forward surge current is 50 amps less, but apart from that they have much the same characteristics.
There's not really any such thing. One common and therefore cheap type of laser diode emits a red light, as does the fairly common (or at least it used to be common; the diodes are so much cheaper I imagine they mostly use them now) laboratory helium-neon laser. So if I had to pick a single color that was "common" I'd say red. There are green and even blue laser diodes now, but they're more expensive than the red ones and therefore aren't as ubiquitous.
A Germanium diode has a much lower breakdown voltage than a silicone diode.
Power = Voltage x Current. So it will be 60W of power consumption, in your case.
nominal 600 watts 610 Watts
The quantity of power consumed by a light bulb is dependant on the wattage of the bulb.
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