actually, inductance is directly proptional to the frequency according to the formula , so if frequency is more, then inductance is also more and vice versa
ohm
Yes. Inductive and capacitive reactance is measured in ohms, and it is entirely possible for reactance to be greater than 1,000, or even 1,000,000, ohms. It all depends on frequency.
Xc(capacitive reactance) = 1/(2piFC)XL(inductive reactance) = 2piFLWhere pi=3.14etc.,F=frequency and C and L are capacitance and inductance.Please pardon lack of proper symbology.
it depends on capacitance and frequency, both inversely. Check your AC circuits textbook for the exact equation.
yes, capacitive reactance is inversely proportional to frequency.
Impedance is the net reactance(for Capacitors and inductors in the circuit) / Resistance of the circcuit whereas reactance is the prperty of the individual passive components ( only capacitors n inductors) to resist the flow of charge.
Inductive reactance is a resistance by inductors to the change of current flow, and is dependent on the frequency at which the current oscillates. DC current flows in only one direction so an inductor's impedance remains the same.
ohm
Inductive reactance is directly proportional to frequency. This means that as the frequency of an AC circuit increases, the inductive reactance also increases. Conversely, as the frequency decreases, the inductive reactance decreases.
Since capacitive reactance is inversely-proportional to the supply frequency, as the frequency is increased, the reactance will decrease.
The reactance of a capacitor depends on its capacitanceand the frequency of the voltage across it.In general, the magnitude of capacitive reactance is . . .1 / (2pi x frequency x capacitance)At 100 Hz, that would be0.00159 / (capacitance) in Farads .
Yes. Inductive and capacitive reactance is measured in ohms, and it is entirely possible for reactance to be greater than 1,000, or even 1,000,000, ohms. It all depends on frequency.
for inductor, reactance XL = 2*pi* f *L, if frequency doubles then reactance increase. But for capacitor, reactance Xc = 1/(2*pi*f*C). In this case if frequency doubles the reactance decrease.
Reactance (in ohms) = 1/(2 pi * capacitance * frequency). Capacitance is in farads. Frequency is in Hertz (cycles/second). So increasing capacitance or increasing frequency will decrease reactance.
The capacitive reactance of a capacitor increases as the frequency decreases.
Xc(capacitive reactance) = 1/(2piFC)XL(inductive reactance) = 2piFLWhere pi=3.14etc.,F=frequency and C and L are capacitance and inductance.Please pardon lack of proper symbology.
it depends on capacitance and frequency, both inversely. Check your AC circuits textbook for the exact equation.