You don't actually have to use a stack, but if your teacher wants that, you can please them:
int fact (int n)
{
int i, fct;
whatever_stack_type_you_have s;
initialize_your_stack (s);
push (s, n);
for (i=1, fct=1; i<n; ++i) fct *= i;
pop (s, &n);
fct *= n;
destroy_your_stack (s);
return fct;
}
== == using recursions: unsigned int Factorial( unsigned int x) { if(x>0) { return ( x * Factorial(x-1)); } else { return(1); } } factorial: unsigned int Factorial( unsigned int x) { unsigned int u32fact = 1; if( x == 0) { return(1); } else { while(x>0) { u32fact = u32fact *x; x--; } } }
Pseudo code+factorial
factorial using recursion style in c++ is unsigned int fact(unsigned int a) { if (a<=1) return 1; else { f*=fact(a-1); return a; } } when using looping structure factorial is unsigned int fact (unsigned int n) { unsigned int i,f=1; for(i=1;i<=n;i++) f*=i ; return f; }
If you really wanted to do this, you could simulate multiplication with repeated addition.
by this program you can find the factorial: #include<iostream> using namespace std; main() { int n,x,f=1; cin>> n; x=0; while(x<n) { x++; f= f*x; } cout<<"factorial is"<<f<<"\n"; system("pause"); return 0; }
== == using recursions: unsigned int Factorial( unsigned int x) { if(x>0) { return ( x * Factorial(x-1)); } else { return(1); } } factorial: unsigned int Factorial( unsigned int x) { unsigned int u32fact = 1; if( x == 0) { return(1); } else { while(x>0) { u32fact = u32fact *x; x--; } } }
chutia mc,bc bhosdika
To find the factorial of each element in an array using pointers in C, you can create a function that takes a pointer to the array and its size as parameters. In the function, iterate through the array using pointer arithmetic, calculating the factorial for each element and storing the result back in the same array or a separate array. For calculating the factorial, you can use a simple loop or recursion. Finally, print or return the modified array with the factorials.
Here's a simple Java program to find the factorial of a given number using a recursive method: import java.util.Scanner; public class Factorial { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.print("Enter a number: "); int number = scanner.nextInt(); System.out.println("Factorial of " + number + " is " + factorial(number)); } static int factorial(int n) { return (n == 0) ? 1 : n * factorial(n - 1); } } This program prompts the user for a number and calculates its factorial recursively.
Pseudo code+factorial
factorial using recursion style in c++ is unsigned int fact(unsigned int a) { if (a<=1) return 1; else { f*=fact(a-1); return a; } } when using looping structure factorial is unsigned int fact (unsigned int n) { unsigned int i,f=1; for(i=1;i<=n;i++) f*=i ; return f; }
#include #include using std::cin;using std::cout;using std::endl;using std::tolower;long factorial(const int& N);int main(){int N = 0; //factorial of Nchar command = 'n';do{cout > N;cout
If you really wanted to do this, you could simulate multiplication with repeated addition.
To calculate the factorial of a number in a shell script, you can use a simple loop. Here's a basic example: #!/bin/bash factorial=1 read -p "Enter a number: " num for (( i=1; i<=num; i++ )) do factorial=$((factorial * i)) done echo "Factorial of $num is $factorial" This script prompts the user for a number, computes its factorial using a for loop, and then prints the result.
Yes. However, they will not be regular stacks.
In Prolog, a simple factorial program can be defined using recursion. Here's a basic implementation: factorial(0, 1). % Base case: factorial of 0 is 1 factorial(N, Result) :- N > 0, N1 is N - 1, factorial(N1, Result1), Result is N * Result1. % Recursive case You can query the factorial of a number by calling factorial(N, Result). where N is the number you want to compute the factorial for.
Kat